Question

Zero element in an Hilbert space is orthogonal?

score 1.1k · Answer 1 · 2026-03-23 07:13:54

1.1k

Views

Zero element in an Hilbert space is orthogonal?

Published on 23 Mar 2026 - 7:13

score 59 · Answer 2 · 2026-03-22 05:57:32

59

Views

Proving vectors are orthogonal

Published on 22 Mar 2026 - 5:57

score 57 · Answer 3 · 2018-01-30 21:55:29

57

Views

$(a\vec{x}+b\vec{v})$ and $(b\vec{x}+a\vec{v})$ are orthogonal. How would you show that $\vec{x}=\vec{0}=\vec{v}$

Published on 30 Jan 2018 - 21:55

score 842 · Answer 4 · 2026-03-22 17:02:36

842

Views

Orthogonal Trajectories in Differential Equations

Published on 22 Mar 2026 - 17:02

score 152 · Answer 5 · 2018-02-05 05:09:51

if $\vec{x},\vec{y} \in \Bbb{R^4}$ with $\vec{x},\vec{y}$ being linearly independent prove that there exists a $\vec{a}$ that is orthogonal to both?

score 232 · Answer 6 · 2026-03-21 22:36:06

232

Views

Gradient of an implicit surface at points not on the surface (clarification)

Published on 21 Mar 2026 - 22:36

score 646 · Answer 7 · 2018-02-06 00:27:07

646

Views

Is the union of the two given sets linearly independent?

Published on 06 Feb 2018 - 0:27

score 45 · Answer 8 · 2018-02-06 11:38:41

45

Views

Orthogonal projection $P_{W_1}P_{W_2} = P_{W_2}P_{W_1}\iff W_1\perp W_2$

Published on 06 Feb 2018 - 11:38

score 99 · Answer 9 · 2026-03-25 04:17:32

99

Views

Geometric Intuition for Adding Projections

Published on 25 Mar 2026 - 4:17

score 88 · Answer 10 · 2018-02-07 22:44:34

88

Views

If $\|u+\lambda v\| \ge \|u\| \forall \lambda$ then $u \perp v$

Published on 07 Feb 2018 - 22:44

score 288 · Answer 11 · 2018-02-07 23:46:29

288

Views

If $\dim (\operatorname{Ker}f)^{\perp} = 1$ then $f$ is continuous for $f$ linear functional on Hilbert space

Published on 07 Feb 2018 - 23:46

score 109 · Answer 12 · 2026-03-25 02:02:17

109

Views

Is there any connection between the fact that a set of vectors are mutually orthogonal and the same set of vectors are linearly independent

Published on 25 Mar 2026 - 2:02

score 466 · Answer 13 · 2026-03-22 06:00:25

466

Views

Either a self-adjoint operator has $n$ eigenvector or not at all

Published on 22 Mar 2026 - 6:00

score 2.2k · Answer 14 · 2018-02-10 02:12:24

2.2k

Views

Prove that if two vectors are orthogonal to another vector, then they are scalar multiples of each other

Published on 10 Feb 2018 - 2:12

score 1k · Answer 15 · 2018-02-10 16:09:54

1k

Views

Linear-Algebra - How to find a position vector of a point S on a plane, that is also perpendicular to the plane

Published on 10 Feb 2018 - 16:09

List Question

Zero element in an Hilbert space is orthogonal?

Proving vectors are orthogonal

$(a\vec{x}+b\vec{v})$ and $(b\vec{x}+a\vec{v})$ are orthogonal. How would you show that $\vec{x}=\vec{0}=\vec{v}$

Orthogonal Trajectories in Differential Equations

if $\vec{x},\vec{y} \in \Bbb{R^4}$ with $\vec{x},\vec{y}$ being linearly independent prove that there exists a $\vec{a}$ that is orthogonal to both?

Gradient of an implicit surface at points not on the surface (clarification)

Is the union of the two given sets linearly independent?

Orthogonal projection $P_{W_1}P_{W_2} = P_{W_2}P_{W_1}\iff W_1\perp W_2$

Geometric Intuition for Adding Projections

If $\|u+\lambda v\| \ge \|u\| \forall \lambda$ then $u \perp v$

If $\dim (\operatorname{Ker}f)^{\perp} = 1$ then $f$ is continuous for $f$ linear functional on Hilbert space

Is there any connection between the fact that a set of vectors are mutually orthogonal and the same set of vectors are linearly independent

Either a self-adjoint operator has $n$ eigenvector or not at all

Prove that if two vectors are orthogonal to another vector, then they are scalar multiples of each other

Linear-Algebra - How to find a position vector of a point S on a plane, that is also perpendicular to the plane

Trending Questions

Popular # Hahtags

Popular Questions