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15
Math.TechQA.Club
2018-06-02 03:47:19
226
Views
If $\frac 1{a+b+c}= \frac 1a+ \frac 1b+ \frac 1c$, then show for odd $n$, $ \frac 1{a^n+b^n+c^n}= \frac 1{a^n}+ \frac 1{b^n}+ \frac 1{c^n}$
Published on
02 Jun 2018 - 3:47
#polynomials
227
Views
Properties of Matrix Polynomials
Published on
02 Jun 2018 - 7:18
#linear-algebra
#matrices
#polynomials
522
Views
Solving the polynomial that doesn't have all the degrees up to the highest one
Published on
02 Jun 2018 - 8:17
#algebra-precalculus
#polynomials
40
Views
Nonzero subdeterminants conjecture: has anybody seen this anywhere?
Published on
27 Mar 2026 - 10:09
#polynomials
#determinant
169
Views
Calculate the $Ker(L_1)$
Published on
28 Mar 2026 - 21:26
#linear-algebra
#matrices
#polynomials
#vector-spaces
#linear-transformations
82
Views
Construct S polynomial using GAP.
Published on
27 Mar 2026 - 9:51
#polynomials
#gap
165
Views
Trouble understanding polynomial GCD
Published on
25 Mar 2026 - 14:28
#polynomials
#gcd-and-lcm
111
Views
How did root of the equation $x= \sqrt{(2-x)(3-x)} + \sqrt{(3-x)(5-x)} + \sqrt{(2-x)(5-x)}$ vanish while solving?
Published on
26 Mar 2026 - 9:58
#polynomials
#quadratics
37
Views
Ring and field of polynomials
Published on
03 Jun 2018 - 10:24
#polynomials
66
Views
Distinction between $\mathbb{K}(\alpha)$ and $\mathbb{K}[\alpha]$
Published on
29 Mar 2026 - 19:25
#abstract-algebra
#polynomials
#ring-theory
#field-theory
194
Views
Prove $\sec^2\frac{\pi}{7}+\sec^2\frac{2\pi}{7}+\sec^2\frac{3\pi}{7}=24$ using the roots of a polynomial
Published on
03 Jun 2018 - 22:11
#trigonometry
#polynomials
65
Views
Decomposition of polynomial into polynomials with non-negative coefficients
Published on
03 Jun 2018 - 23:49
#polynomials
320
Views
Multivariate polynomials with infinite number of zeros
Published on
04 Jun 2018 - 1:53
#linear-algebra
#polynomials
95
Views
Weak Nullstellensatz in practice
Published on
25 Mar 2026 - 11:17
#algebraic-geometry
#polynomials
#commutative-algebra
#irreducible-polynomials
59
Views
Is $\sqrt[n]{x} = 0$ an algebraic equation?
Published on
04 Jun 2018 - 14:39
#functions
#polynomials
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