Question

Can I find a power series expansion of this function without a Taylor series?

score 85 · Answer 1 · 2026-04-12 12:50:03

85

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Can I find a power series expansion of this function without a Taylor series?

Published on 12 Apr 2026 - 12:50

score 39 · Answer 2 · 2020-06-27 11:30:56

39

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Power Series ODE Question - Final Step

Published on 27 Jun 2020 - 11:30

score 46 · Answer 3 · 2026-04-12 10:23:27

46

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Power series problems

Published on 12 Apr 2026 - 10:23

score 55 · Answer 4 · 2020-06-29 12:28:31

55

Views

Show that $\sum_{n = 2}^{\infty} \left(\frac{(-1)^{n}}{(n-1)n} - \frac{9(-1)^n}{2\cdot 3^n}\right)x^n > 0$ for positive $x$.

Published on 29 Jun 2020 - 12:28

score 165 · Answer 5 · 2026-04-12 16:55:17

165

Views

Find multiplicative inverse of formal power series

Published on 12 Apr 2026 - 16:55

score 139 · Answer 6 · 2026-04-10 03:50:20

139

Views

Root test for complex series and cancelling powers with absolute values

Published on 10 Apr 2026 - 3:50

score 28 · Answer 7 · 2020-07-02 12:24:19

28

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Calculate a meromorphic function on $\mathbb{C}$ s.t. $g(z) = \sum_{n\geq0}(n+1)T^n$

Published on 02 Jul 2020 - 12:24

score 217 · Answer 8 · 2026-04-12 20:51:34

217

Views

Polynomial bound for complex exponential function

Published on 12 Apr 2026 - 20:51

score 49 · Answer 9 · 2026-04-12 12:46:03

49

Views

Is there an efficient way to calculate the following power series?

Published on 12 Apr 2026 - 12:46

score 277 · Answer 10 · 2026-04-03 12:14:36

277

Views

Show that if $|z| < 1$ then the series $\sum_{n=0}^{\infty}(n+1)z^{n}$ converges, and find its sum.

Published on 03 Apr 2026 - 12:14

score 239 · Answer 11 · 2026-04-10 12:02:58

239

Views

How can I prove that this function is bounded?

Published on 10 Apr 2026 - 12:02

score 64 · Answer 12 · 2026-04-11 16:51:54

64

Views

What is wrong in the following method of obtaining the Maclaurin series of $\frac{2x}{e^{2x}-1}$?

Published on 11 Apr 2026 - 16:51

score 66 · Answer 13 · 2020-07-05 13:55:33

66

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Convergence of the series $\sum_{n=1}^k\frac{k(n+1)}{k-n+1}\theta^{n}$

Published on 05 Jul 2020 - 13:55

score 130 · Answer 14 · 2020-07-05 17:05:45

130

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Find the Sum of the Series $\sum_{n=0}^\infty \frac{3n^2 -1}{(n+1)!}$

Published on 05 Jul 2020 - 17:05

score 265 · Answer 15 · 2026-04-13 00:32:32

265

Views

Can this integral be expanded as a power series?

Published on 13 Apr 2026 - 0:32

List Question

Can I find a power series expansion of this function without a Taylor series?

Power Series ODE Question - Final Step

Power series problems

Show that $\sum_{n = 2}^{\infty} \left(\frac{(-1)^{n}}{(n-1)n} - \frac{9(-1)^n}{2\cdot 3^n}\right)x^n > 0$ for positive $x$.

Find multiplicative inverse of formal power series

Root test for complex series and cancelling powers with absolute values

Calculate a meromorphic function on $\mathbb{C}$ s.t. $g(z) = \sum_{n\geq0}(n+1)T^n$

Polynomial bound for complex exponential function

Is there an efficient way to calculate the following power series?

Show that if $|z| < 1$ then the series $\sum_{n=0}^{\infty}(n+1)z^{n}$ converges, and find its sum.

How can I prove that this function is bounded?

What is wrong in the following method of obtaining the Maclaurin series of $\frac{2x}{e^{2x}-1}$?

Convergence of the series $\sum_{n=1}^k\frac{k(n+1)}{k-n+1}\theta^{n}$

Find the Sum of the Series $\sum_{n=0}^\infty \frac{3n^2 -1}{(n+1)!}$

Can this integral be expanded as a power series?

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