Question

On simple calculations with $\sum_{k=1}^{n-1}\left\lfloor{\frac{km}{n}}\right\rfloor=\frac{1}{2}(m-1)(n-1)$ and primes $m$ and $n$

score 91 · Answer 1 · 2026-03-29 20:01:22

91

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On simple calculations with $\sum_{k=1}^{n-1}\left\lfloor{\frac{km}{n}}\right\rfloor=\frac{1}{2}(m-1)(n-1)$ and primes $m$ and $n$

Published on 29 Mar 2026 - 20:01

score 9k · Answer 2 · 2026-03-30 20:12:33

9k

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Mathematical induction problem: $\frac12\cdot \frac34\cdots\frac{2n-1}{2n}<\frac1{\sqrt{2n}}$

Published on 30 Mar 2026 - 20:12

score 898 · Answer 3 · 2016-08-29 01:58:21

898

Views

What happens when the product of Sigma Algebras is taken over an uncountable set??

Published on 29 Aug 2016 - 1:58

score 465 · Answer 4 · 2026-03-25 20:33:59

465

Views

diagonalizing a hadamard product

Published on 25 Mar 2026 - 20:33

score 746 · Answer 5 · 2016-09-01 14:12:51

746

Views

upper bound to product of square roots as function of their arguments

Published on 01 Sep 2016 - 14:12

score 399 · Answer 6 · 2016-09-03 17:28:26

399

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What is the maximum product from two fractions who sum to 1?

Published on 03 Sep 2016 - 17:28

score 706 · Answer 7 · 2016-09-06 15:23:57

706

Views

relationship between scalar product and tensor product

Published on 06 Sep 2016 - 15:23

score 637 · Answer 8 · 2016-09-07 18:12:38

637

Views

Generalizing a Trig Identity

Published on 07 Sep 2016 - 18:12

score 108 · Answer 9 · 2016-09-09 12:18:47

108

Views

Example of a function $f : A \times B \to X$ that isn't continuous but every $f_a : B \to X, f_b : A \to X$ is

Published on 09 Sep 2016 - 12:18

score 1.8k · Answer 10 · 2016-09-09 13:43:09

1.8k

Views

What is a good upper bound $n^n(n-1)^{n-1}\ldots2^21^1$?

Published on 09 Sep 2016 - 13:43

score 86 · Answer 11 · 2016-09-12 02:04:32

86

Views

Product topology on n copies of $\mathbb{R}$

Published on 12 Sep 2016 - 2:04

score 497 · Answer 12 · 2016-09-15 09:49:02

497

Views

If $f(x)$ is measurable then $g(x,y)=f(x)-y$ is measurable

Published on 15 Sep 2016 - 9:49

score 101 · Answer 13 · 2016-09-18 13:25:36

101

Views

Show that factorization of a $n - 1$ degree polynomial is $P(z) = \prod_{k=1}^{n - 1} (z^2 - 2z\cos(\frac{k\pi}{n}) + 1)$

Published on 18 Sep 2016 - 13:25

score 300 · Answer 14 · 2026-03-30 17:00:51

300

Views

Multiplication of two constant symmetric tensors

Published on 30 Mar 2026 - 17:00

score 130 · Answer 15 · 2016-09-22 02:21:26

130

Views

An infinite product of roots of x+1

Published on 22 Sep 2016 - 2:21

List Question

On simple calculations with $\sum_{k=1}^{n-1}\left\lfloor{\frac{km}{n}}\right\rfloor=\frac{1}{2}(m-1)(n-1)$ and primes $m$ and $n$

Mathematical induction problem: $\frac12\cdot \frac34\cdots\frac{2n-1}{2n}<\frac1{\sqrt{2n}}$

What happens when the product of Sigma Algebras is taken over an uncountable set??

diagonalizing a hadamard product

upper bound to product of square roots as function of their arguments

What is the maximum product from two fractions who sum to 1?

relationship between scalar product and tensor product

Generalizing a Trig Identity

Example of a function $f : A \times B \to X$ that isn't continuous but every $f_a : B \to X, f_b : A \to X$ is

What is a good upper bound $n^n(n-1)^{n-1}\ldots2^21^1$?

Product topology on n copies of $\mathbb{R}$

If $f(x)$ is measurable then $g(x,y)=f(x)-y$ is measurable

Show that factorization of a $n - 1$ degree polynomial is $P(z) = \prod_{k=1}^{n - 1} (z^2 - 2z\cos(\frac{k\pi}{n}) + 1)$

Multiplication of two constant symmetric tensors

An infinite product of roots of x+1

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