Question

The product of composite numbers in the range $[m+2, 2m+2]$ is not less than $m!$.

score 68 · Answer 1 · 2017-04-30 12:06:54

68

Views

The product of composite numbers in the range $[m+2, 2m+2]$ is not less than $m!$.

Published on 30 Apr 2017 - 12:06

score 631 · Answer 2 · 2017-04-30 14:30:53

631

Views

Unknown syntax with multiplication?

Published on 30 Apr 2017 - 14:30

score 875 · Answer 3 · 2017-05-01 16:34:40

875

Views

Prove $\frac1{2}\cdot\frac3{4}\cdot\frac5{6}\cdot...\cdot\frac{2n-1}{2n}\le \frac{1}{\sqrt{3n+1}}$

Published on 01 May 2017 - 16:34

score 47 · Answer 4 · 2017-05-01 18:26:18

47

Views

Eliminate productory

Published on 01 May 2017 - 18:26

score 339 · Answer 5 · 2017-05-04 16:51:02

339

Views

Proof by induction $1\cdot 3 \cdot 5\cdots (2n-1) / (2 \cdot 4\cdot 6\cdots 2n) \leq 1/ \sqrt{n+1}, \forall n \geq 1, n\in \mathbb N$

Published on 04 May 2017 - 16:51

score 114 · Answer 6 · 2017-05-05 13:36:03

114

Views

Standard notation for building records from sets

Published on 05 May 2017 - 13:36

score 253 · Answer 7 · 2017-05-06 21:08:34

253

Views

Inequality on Matrix Weighted Norm

Published on 06 May 2017 - 21:08

score 474 · Answer 8 · 2017-05-07 01:30:55

474

Views

Showing that $ \sum_{n=1}^{m} \prod_{k=1}^n \frac{2k-1}{2k} = \frac{2(m+1)\Gamma(m+\frac{3}{2})}{\sqrt{\pi}\Gamma(m+2)}$

Published on 07 May 2017 - 1:30

score 57 · Answer 9 · 2017-05-13 01:35:25

57

Views

I need to simplify following product $\frac{\prod_{1\leq j <i \leq n}(i-j)(i-j)}{\prod_{1\leq i,j\leq n}(i+j-1)}$

Published on 13 May 2017 - 1:35

score 147 · Answer 10 · 2017-05-13 04:56:26

147

Views

Closed form for finite product $\prod\limits_{j=1}^k\frac{n+j}{n-j}$

Published on 13 May 2017 - 4:56

score 647 · Answer 11 · 2017-05-15 15:08:29

647

Views

How do I differentiate a product $a(x) b(x) c(x)$ of three functions?

Published on 15 May 2017 - 15:08

score 3.5k · Answer 12 · 2017-05-15 19:34:35

3.5k

Views

How to calculate the product of a sequence?

Published on 15 May 2017 - 19:34

score 32 · Answer 13 · 2017-05-17 22:06:47

32

Views

Finite join of binary Cartesian products and identity relation

Published on 17 May 2017 - 22:06

score 58 · Answer 14 · 2026-03-30 09:28:44

58

Views

Why isn't the composition equal to the product?

Published on 30 Mar 2026 - 9:28

score 1.3k · Answer 15 · 2017-05-20 14:26:30

1.3k

Views

Absolute value of the sum of complex numbers squared as product

Published on 20 May 2017 - 14:26

List Question

The product of composite numbers in the range $[m+2, 2m+2]$ is not less than $m!$.

Unknown syntax with multiplication?

Prove $\frac1{2}\cdot\frac3{4}\cdot\frac5{6}\cdot...\cdot\frac{2n-1}{2n}\le \frac{1}{\sqrt{3n+1}}$

Eliminate productory

Proof by induction $1\cdot 3 \cdot 5\cdots (2n-1) / (2 \cdot 4\cdot 6\cdots 2n) \leq 1/ \sqrt{n+1}, \forall n \geq 1, n\in \mathbb N$

Standard notation for building records from sets

Inequality on Matrix Weighted Norm

Showing that $ \sum_{n=1}^{m} \prod_{k=1}^n \frac{2k-1}{2k} = \frac{2(m+1)\Gamma(m+\frac{3}{2})}{\sqrt{\pi}\Gamma(m+2)}$

I need to simplify following product $\frac{\prod_{1\leq j <i \leq n}(i-j)(i-j)}{\prod_{1\leq i,j\leq n}(i+j-1)}$

Closed form for finite product $\prod\limits_{j=1}^k\frac{n+j}{n-j}$

How do I differentiate a product $a(x) b(x) c(x)$ of three functions?

How to calculate the product of a sequence?

Finite join of binary Cartesian products and identity relation

Why isn't the composition equal to the product?

Absolute value of the sum of complex numbers squared as product

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