Given $\textbf{P} = \textbf{X}(\textbf{X}^{\prime}\textbf{X})^{-1}\textbf{X}^{\prime}$, prove that $\mathcal{C}(\textbf{P}) = \mathcal{C}(\textbf{X})$

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Given $\textbf{P} = \textbf{X}(\textbf{X}^{\prime}\textbf{X})^{-1}\textbf{X}^{\prime}$, prove that $\mathcal{C}(\textbf{P}) = \mathcal{C}(\textbf{X})$

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