List questions from quadratic-reciprocity

Published on 01 Nov 2013 - 21:56

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Solve quadratic congruence using the Chinese Remainder Theorem

Published on 02 Nov 2013 - 22:52

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When is the quadratic congruence $ax^2 + bx +c \equiv 0 \pmod p$ solvable?

Published on 04 Nov 2013 - 16:14

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Show that prime $p=4n+1$ is a divisor of $n^{n}-1$

Published on 05 Nov 2013 - 20:21

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Show that $x^2\equiv a \pmod {2^n}$ has a solution where $a\equiv1 \pmod 8$ and $n\ge3$

Published on 08 Nov 2013 - 3:05

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Quadratic Reciprocity

Published on 25 Nov 2013 - 22:05

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Prove that $\left(\frac2p\right) = 1$ if $p \equiv 1,7 \pmod 8$ and $\left(\frac2p\right) = -1$ if $p \equiv 3,5 \pmod 8$ using ring theory

Published on 05 Dec 2013 - 13:32

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Quadratic character of 3

Published on 12 Dec 2013 - 20:34

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Suppose $p$ and $q$ are odd primes and $p = q + 4a$ for some $a$. Prove that $(\frac ap) = (\frac aq)$ holds.

Published on 16 Dec 2013 - 20:55

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$2^{4n+1} \equiv 1 \pmod{8n+7}$, this has been bugging me

Published on 19 Dec 2013 - 11:45

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Legendre symbols (p/q) = (a/q)

Published on 19 Dec 2013 - 21:26

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What is the point of quadratic residues?

Published on 20 Dec 2013 - 10:51

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Number of elements that exist so $b^3 \equiv a\pmod n$, when n is composed of p and q who are prime numbers

Published on 26 Dec 2013 - 18:27

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Jacobi symbol $\left(\frac{(n+1)/2}{n}\right)$

Published on 03 Jan 2014 - 16:04

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Quadratic Reciprocity Joke

Published on 06 Jan 2014 - 8:35

List Question

Number Theory: Solutions of $ax^2+by^2\equiv1 \pmod p$

Solve quadratic congruence using the Chinese Remainder Theorem

When is the quadratic congruence $ax^2 + bx +c \equiv 0 \pmod p$ solvable?

Show that prime $p=4n+1$ is a divisor of $n^{n}-1$

Show that $x^2\equiv a \pmod {2^n}$ has a solution where $a\equiv1 \pmod 8$ and $n\ge3$

Quadratic Reciprocity

Prove that $\left(\frac2p\right) = 1$ if $p \equiv 1,7 \pmod 8$ and $\left(\frac2p\right) = -1$ if $p \equiv 3,5 \pmod 8$ using ring theory

Quadratic character of 3

Suppose $p$ and $q$ are odd primes and $p = q + 4a$ for some $a$. Prove that $(\frac ap) = (\frac aq)$ holds.

$2^{4n+1} \equiv 1 \pmod{8n+7}$, this has been bugging me

Legendre symbols (p/q) = (a/q)

What is the point of quadratic residues?

Number of elements that exist so $b^3 \equiv a\pmod n$, when n is composed of p and q who are prime numbers

Jacobi symbol $\left(\frac{(n+1)/2}{n}\right)$

Quadratic Reciprocity Joke

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