Question

Looking for a quicker way to solve a quadratic problem

score 50 · Answer 1 · 2017-03-14 19:10:24

50

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Looking for a quicker way to solve a quadratic problem

Published on 14 Mar 2017 - 19:10

score 1.3k · Answer 2 · 2017-03-14 20:49:34

1.3k

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Derivation of the quadratic formula for complex coefficients

Published on 14 Mar 2017 - 20:49

score 629 · Answer 3 · 2017-03-16 10:09:09

629

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Using TI Nspire to store variables and carry out a defined equation

Published on 16 Mar 2017 - 10:09

score 63 · Answer 4 · 2017-03-17 16:40:34

63

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Quadratic Equations and their Roots

Published on 17 Mar 2017 - 16:40

score 54 · Answer 5 · 2017-03-18 16:17:59

54

Views

Find value or $W=\sqrt[4x+4]{3^{x}\left ( \sqrt{5}-1 \right )}$ according to condition $9^{x}=6^x +4^x$

Published on 18 Mar 2017 - 16:17

score 95 · Answer 6 · 2017-03-19 06:17:18

95

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If 'x' is real and $\frac{x^2-x+c}{x^2+x+2c}$ can take all real values find the interval in which $c$ lies

Published on 19 Mar 2017 - 6:17

score 4.4k · Answer 7 · 2017-03-19 07:00:50

4.4k

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The equations $x^3+5x^2+px+q=0$and $x^3+7x^2+px+r=0$ have 2 common roots, then find the third root of both equations

Published on 19 Mar 2017 - 7:00

score 1k · Answer 8 · 2017-03-19 07:20:54

If $a>b>0$ and $a^3+b^3+27ab=729$ then $ax^2+bx-9=0$ has roots $\alpha,\beta,(\alpha<\beta)$. Find the value of $4\beta -a\alpha$.

score 1k · Answer 9 · 2017-03-19 08:35:52

1k

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If $x^2+\lambda x+1=0, \lambda$ is part of $(-2,2)$ and $4x^3+3x+2c=0$ have common root then $c+\lambda$ can be

Published on 19 Mar 2017 - 8:35

score 42 · Answer 10 · 2017-03-19 14:10:24

42

Views

Showing a trinomial is always positive

Published on 19 Mar 2017 - 14:10

score 516 · Answer 11 · 2017-03-19 17:31:54

516

Views

Show that the equation $2x^2+(6+p)x+3p=0$ has real roots for all real values of $p$

Published on 19 Mar 2017 - 17:31

score 350 · Answer 12 · 2017-03-20 19:57:13

350

Views

A quadrature formula, proving weights are equal to 1?

Published on 20 Mar 2017 - 19:57

score 466 · Answer 13 · 2026-03-25 13:56:17

466

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How to prove that $f(x)=ax^2+bx+c=0$ has a unique solution, provided that $\forall x :f(x) \geq 0$?

Published on 25 Mar 2026 - 13:56

score 912 · Answer 14 · 2017-03-22 05:04:57

912

Views

The quickest way to solve a quadratic equation with imaginary solution

Published on 22 Mar 2017 - 5:04

score 334 · Answer 15 · 2017-03-23 03:11:30

334

Views

maximize profit based on rate of sales

Published on 23 Mar 2017 - 3:11

List Question

Looking for a quicker way to solve a quadratic problem

Derivation of the quadratic formula for complex coefficients

Using TI Nspire to store variables and carry out a defined equation

Quadratic Equations and their Roots

Find value or $W=\sqrt[4x+4]{3^{x}\left ( \sqrt{5}-1 \right )}$ according to condition $9^{x}=6^x +4^x$

If 'x' is real and $\frac{x^2-x+c}{x^2+x+2c}$ can take all real values find the interval in which $c$ lies

The equations $x^3+5x^2+px+q=0$and $x^3+7x^2+px+r=0$ have 2 common roots, then find the third root of both equations

If $a>b>0$ and $a^3+b^3+27ab=729$ then $ax^2+bx-9=0$ has roots $\alpha,\beta,(\alpha<\beta)$. Find the value of $4\beta -a\alpha$.

If $x^2+\lambda x+1=0, \lambda$ is part of $(-2,2)$ and $4x^3+3x+2c=0$ have common root then $c+\lambda$ can be

Showing a trinomial is always positive

Show that the equation $2x^2+(6+p)x+3p=0$ has real roots for all real values of $p$

A quadrature formula, proving weights are equal to 1?

How to prove that $f(x)=ax^2+bx+c=0$ has a unique solution, provided that $\forall x :f(x) \geq 0$?

The quickest way to solve a quadratic equation with imaginary solution

maximize profit based on rate of sales

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