Question

Prove the inequality - inequality involving surds

score 229 · Answer 1 · 2015-08-08 11:41:27

229

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Prove the inequality - inequality involving surds

Published on 08 Aug 2015 - 11:41

score 703 · Answer 2 · 2026-03-26 19:19:02

703

Views

Follow-up Question: Proof of Irrationality of $\sqrt{3}$

Published on 26 Mar 2026 - 19:19

score 318 · Answer 3 · 2026-04-04 04:02:21

318

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Why does the elliptic curve for $a+b+c = abc = 6$ involve a solvable nonic?

Published on 04 Apr 2026 - 4:02

score 85 · Answer 4 · 2015-08-11 21:47:35

85

Views

What will change if we admit a different definition of $\sqrt a$

Published on 11 Aug 2015 - 21:47

score 123 · Answer 5 · 2015-08-12 01:04:39

123

Views

Proving limit of difference is $0$: $\lim_{n\rightarrow\infty} [(n+1)^{\frac{1}{7}} - (n)^{\frac{1}{7}}] = 0$

Published on 12 Aug 2015 - 1:04

score 443 · Answer 6 · 2026-04-02 20:06:25

443

Views

algebra problem, Solve the equation

Published on 02 Apr 2026 - 20:06

score 306 · Answer 7 · 2015-08-12 07:14:12

306

Views

Show that $1/\sqrt{1} + 1/\sqrt{2} + ... + 1/\sqrt{n} \leq 2\sqrt{n}-1$

Published on 12 Aug 2015 - 7:14

score 117 · Answer 8 · 2026-03-26 04:29:29

117

Views

Simplifying $\frac{1}{\sqrt{-1}}$

Published on 26 Mar 2026 - 4:29

score 1.6k · Answer 9 · 2026-03-26 19:20:15

1.6k

Views

Proof of the irrationality of $\sqrt n$, where $n$ is square free

Published on 26 Mar 2026 - 19:20

score 11.9k · Answer 10 · 2015-08-15 07:04:57

Value of $\frac{\sqrt{10+\sqrt{1}}+\sqrt{10+\sqrt{2}}+\cdots+\sqrt{10+\sqrt{99}} }{\sqrt{10-\sqrt{1}}+\sqrt{10-\sqrt{2}}+\cdots+\sqrt{10-\sqrt{99}}}$

score 141 · Answer 11 · 2026-04-03 14:27:26

141

Views

Solve limit using Stolz's theorem: $\lim_{n\to\infty} \frac{n}{\sqrt[n]{n!}}$

Published on 03 Apr 2026 - 14:27

score 168 · Answer 12 · 2026-04-01 00:25:26

168

Views

Square root of whole number number of solutions

Published on 01 Apr 2026 - 0:25

score 109 · Answer 13 · 2026-03-26 19:01:50

109

Views

Is it possible that some combination of partial sums of $\sum \sqrt{k}$ be a rational number? $\text{where } k \text { not a perfect square}$

Published on 26 Mar 2026 - 19:01

score 628 · Answer 14 · 2015-08-18 14:56:17

628

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Find $\lim\limits_{n\to+\infty}\sqrt[n]{\prod\limits_{k=1}^{n}{n\choose k}}$

Published on 18 Aug 2015 - 14:56

score 144 · Answer 15 · 2026-04-03 16:18:28

144

Views

Finding a positive lower bound of the sequence $\frac{\sqrt[n]{n!}}n$

Published on 03 Apr 2026 - 16:18

List Question

Prove the inequality - inequality involving surds

Follow-up Question: Proof of Irrationality of $\sqrt{3}$

Why does the elliptic curve for $a+b+c = abc = 6$ involve a solvable nonic?

What will change if we admit a different definition of $\sqrt a$

Proving limit of difference is $0$: $\lim_{n\rightarrow\infty} [(n+1)^{\frac{1}{7}} - (n)^{\frac{1}{7}}] = 0$

algebra problem, Solve the equation

Show that $1/\sqrt{1} + 1/\sqrt{2} + ... + 1/\sqrt{n} \leq 2\sqrt{n}-1$

Simplifying $\frac{1}{\sqrt{-1}}$

Proof of the irrationality of $\sqrt n$, where $n$ is square free

Value of $\frac{\sqrt{10+\sqrt{1}}+\sqrt{10+\sqrt{2}}+\cdots+\sqrt{10+\sqrt{99}} }{\sqrt{10-\sqrt{1}}+\sqrt{10-\sqrt{2}}+\cdots+\sqrt{10-\sqrt{99}}}$

Solve limit using Stolz's theorem: $\lim_{n\to\infty} \frac{n}{\sqrt[n]{n!}}$

Square root of whole number number of solutions

Is it possible that some combination of partial sums of $\sum \sqrt{k}$ be a rational number? $\text{where } k \text { not a perfect square}$

Find $\lim\limits_{n\to+\infty}\sqrt[n]{\prod\limits_{k=1}^{n}{n\choose k}}$

Finding a positive lower bound of the sequence $\frac{\sqrt[n]{n!}}n$

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