Question

How to find $\lim\limits_{x~\to~4}\frac{\sqrt{2x+1}-3}{\sqrt{x-2}-\sqrt{2}}$

score 2.4k · Answer 1 · 2015-10-02 20:29:29

2.4k

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How to find $\lim\limits_{x~\to~4}\frac{\sqrt{2x+1}-3}{\sqrt{x-2}-\sqrt{2}}$

Published on 02 Oct 2015 - 20:29

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104

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score 318 · Answer 7 · 2015-10-05 07:07:00

318

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score 57 · Answer 8 · 2015-10-05 08:38:22

57

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score 64 · Answer 9 · 2015-10-05 16:01:25

64

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score 71 · Answer 10 · 2015-10-05 19:36:09

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score 36 · Answer 11 · 2015-10-06 15:38:24

36

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score 562 · Answer 12 · 2026-03-29 16:23:10

562

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score 635 · Answer 13 · 2026-04-03 23:05:02

635

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score 164 · Answer 14 · 2026-03-28 08:45:38

164

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score 367 · Answer 15 · 2015-10-09 08:00:19

367

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Published on 09 Oct 2015 - 8:00

List Question

How to find $\lim\limits_{x~\to~4}\frac{\sqrt{2x+1}-3}{\sqrt{x-2}-\sqrt{2}}$

How do I work out ${10\sqrt 30}\over{ 5\sqrt5}$ $?$

How to multiply radicals?

When is area of regular $n$-gon expressible by radicals?

Finding the $1000$-th decimal of $\sqrt{1111...111}$

limit of a radical function

How can I prove that $\lim_{n \rightarrow \infty} \sqrt[n]x=1$

Calculate the radicals

Simplify the expresion

How to answer this kind of questions

Solve for x (radicals)

Assuming convergence of the following series, find the value of $\sqrt{6+\sqrt{6+\sqrt{6+...}}}$

Computation of a limit involving factorial $\lim_{n \to \infty} \sqrt[n+1] {(n+1)!} - \sqrt[n] {(n)!} = \frac{1}{e}$

$\sqrt2^{\sqrt3 }$ $<$ $\sqrt3^{\sqrt2 }$ geometrical way

Why does $\sqrt{2x+15}-6=x$ have an "imposter" solution?

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