List questions from radicals

Published on 28 Mar 2026 - 15:57

69

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Calculate the radicals (order 3)

Published on 18 Oct 2015 - 13:37

72

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What is the best way of resolving an expression with square roots in denominator?

Published on 06 Apr 2026 - 6:19

329

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Proving $\sqrt[4]{4}$ is irrational

Published on 26 Mar 2026 - 20:43

163

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Why does $\sqrt{8^2+(8\sqrt 3)^2}=16$

Published on 20 Oct 2015 - 8:09

573

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Is $(\sqrt{-x})^2$ equal to $x$ or $-x$?

Published on 20 Oct 2015 - 16:02

111

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Is $\sqrt{90x^2}$ fully simplified?

Published on 21 Oct 2015 - 14:52

127

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Prove $\sqrt{n+1} - \sqrt{n} \to 0$ as $n \to \infty$

Published on 22 Oct 2015 - 8:09

221

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General form of $\sqrt{a - b} - \sqrt{a + b}$?

Published on 23 Oct 2015 - 18:19

138

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Why aren't square roots written between vertical bars (absolute value)?

Published on 23 Oct 2015 - 19:27

141

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High school level radical expression

Published on 24 Oct 2015 - 1:26

2.4k

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Evaluate the nested square root $x = \sqrt{11 - 2\sqrt{10}} - \sqrt{11 + 2\sqrt{10}}$

Published on 30 Mar 2026 - 23:46

278

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The inequality $\limsup \frac{c_{n+1}}{c_n} \geqslant \limsup \sqrt[n]{c_n}$

Published on 02 Apr 2026 - 19:15

753

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Why is $\lim_{x \to \infty} (\sqrt{9x^2+x}-3x)=\frac{1}{6}$?

Published on 28 Oct 2015 - 23:18

173

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Proof by induction: $2(\sqrt n - 1) < \sum\limits_{i=1}^n \left(\frac{1}{\sqrt{i}}\right)$

Published on 29 Oct 2015 - 9:31

List Question

Square root of continued fraction

Calculate the radicals (order 3)

What is the best way of resolving an expression with square roots in denominator?

Proving $\sqrt[4]{4}$ is irrational

Why does $\sqrt{8^2+(8\sqrt 3)^2}=16$

Is $(\sqrt{-x})^2$ equal to $x$ or $-x$?

Is $\sqrt{90x^2}$ fully simplified?

Prove $\sqrt{n+1} - \sqrt{n} \to 0$ as $n \to \infty$

General form of $\sqrt{a - b} - \sqrt{a + b}$?

Why aren't square roots written between vertical bars (absolute value)?

High school level radical expression

Evaluate the nested square root $x = \sqrt{11 - 2\sqrt{10}} - \sqrt{11 + 2\sqrt{10}}$

The inequality $\limsup \frac{c_{n+1}}{c_n} \geqslant \limsup \sqrt[n]{c_n}$

Why is $\lim_{x \to \infty} (\sqrt{9x^2+x}-3x)=\frac{1}{6}$?

Proof by induction: $2(\sqrt n - 1) < \sum\limits_{i=1}^n \left(\frac{1}{\sqrt{i}}\right)$

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