Question

How to find $\lim\limits_{n\to\infty} n·(\sqrt[n]{a}-1)$?

score 917 · Answer 1 · 2026-04-13 09:20:16

917

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How to find $\lim\limits_{n\to\infty} n·(\sqrt[n]{a}-1)$?

Published on 13 Apr 2026 - 9:20

score 729 · Answer 2 · 2026-04-16 07:14:38

729

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How to find the limit $\lim\limits _{ x\to \infty } \left( \sqrt { x^2+3x } -\sqrt { x^2+x } \right) $?

Published on 16 Apr 2026 - 7:14

score 1.4k · Answer 3 · 2026-04-16 08:17:10

1.4k

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Evaluating the limit: $\lim \limits_{n\to \infty}\sqrt[n]{4^n+9n^2}=4$

Published on 16 Apr 2026 - 8:17

score 1.8k · Answer 4 · 2026-04-15 21:11:37

1.8k

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Find the value of : $\lim_{x \to \infty} \sqrt{4x^2 + 4} - (2x + 2)$

Published on 15 Apr 2026 - 21:11

score 615 · Answer 5 · 2026-04-16 03:04:30

615

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Limits of convergent/divergent sequences (revision): $\lim\limits_{n \to \infty} \sqrt[n] {100n+25+6^n}$

Published on 16 Apr 2026 - 3:04

score 20.6k · Answer 6 · 2026-04-10 19:03:52

20.6k

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How to write such $\sqrt{\sqrt{x}}$ in equation?

Published on 10 Apr 2026 - 19:03

score 4.5k · Answer 7 · 2026-04-09 19:48:25

4.5k

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Square Root Of A Square Root Of A Square Root

Published on 09 Apr 2026 - 19:48

score 351 · Answer 8 · 2026-04-16 08:16:52

351

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Evaluating Limit Question $\lim\limits_{n\to \infty}\ \frac{1+\sqrt[2]{2}+\sqrt[3]{3}+\cdots+\sqrt[n]{n}}{n}=1$?

Published on 16 Apr 2026 - 8:16

score 1.2k · Answer 9 · 2026-04-14 19:51:39

1.2k

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Proving that: $\lim\limits_{n\to\infty} \left(\frac{a^{\frac{1}{n}}+b^{\frac{1}{n}}}{2}\right)^n =\sqrt{ab}$

Published on 14 Apr 2026 - 19:51

score 14.1k · Answer 10 · 2026-04-16 10:02:33

14.1k

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Calculate $\lim_{n\to{+}\infty}{(\sqrt{n^{2}+n}-n)}$

Published on 16 Apr 2026 - 10:02

score 19.7k · Answer 11 · 2026-04-14 20:36:03

19.7k

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$\lim\limits_{n \to{+}\infty}{\sqrt[n]{n!}}$ is infinite

Published on 14 Apr 2026 - 20:36

score 577 · Answer 12 · 2026-04-15 11:37:00

577

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System of two Equations: $\sqrt x+y=11$ and $\sqrt y+x=7$

Published on 15 Apr 2026 - 11:37

score 43.7k · Answer 13 · 2026-04-17 13:08:21

43.7k

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Using conjugates to find a limit with a cubic root: $\lim_{h\to 0}\frac{\sqrt[3]{h+1}-1}{h}$

Published on 17 Apr 2026 - 13:08

score 31.9k · Answer 14 · 2026-04-17 02:31:10

31.9k

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Limit of the sequence $\lim_{n\rightarrow\infty}\sqrt[n]n$

Published on 17 Apr 2026 - 2:31

score 947 · Answer 15 · 2026-04-15 03:37:09

947

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Limit exercise from Rudin: $\lim\limits_{n \to \infty} \sqrt{n^2+n} -n$

Published on 15 Apr 2026 - 3:37

List Question

How to find $\lim\limits_{n\to\infty} n·(\sqrt[n]{a}-1)$?

How to find the limit $\lim\limits _{ x\to \infty } \left( \sqrt { x^2+3x } -\sqrt { x^2+x } \right) $?

Evaluating the limit: $\lim \limits_{n\to \infty}\sqrt[n]{4^n+9n^2}=4$

Find the value of : $\lim_{x \to \infty} \sqrt{4x^2 + 4} - (2x + 2)$

Limits of convergent/divergent sequences (revision): $\lim\limits_{n \to \infty} \sqrt[n] {100n+25+6^n}$

How to write such $\sqrt{\sqrt{x}}$ in equation?

Square Root Of A Square Root Of A Square Root

Evaluating Limit Question $\lim\limits_{n\to \infty}\ \frac{1+\sqrt[2]{2}+\sqrt[3]{3}+\cdots+\sqrt[n]{n}}{n}=1$?

Proving that: $\lim\limits_{n\to\infty} \left(\frac{a^{\frac{1}{n}}+b^{\frac{1}{n}}}{2}\right)^n =\sqrt{ab}$

Calculate $\lim_{n\to{+}\infty}{(\sqrt{n^{2}+n}-n)}$

$\lim\limits_{n \to{+}\infty}{\sqrt[n]{n!}}$ is infinite

System of two Equations: $\sqrt x+y=11$ and $\sqrt y+x=7$

Using conjugates to find a limit with a cubic root: $\lim_{h\to 0}\frac{\sqrt[3]{h+1}-1}{h}$

Limit of the sequence $\lim_{n\rightarrow\infty}\sqrt[n]n$

Limit exercise from Rudin: $\lim\limits_{n \to \infty} \sqrt{n^2+n} -n$

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