Question

Can i factor this expression: $x^3+y^3+z^3$

score 179 · Answer 1 · 2026-03-27 23:40:23

179

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Can i factor this expression: $x^3+y^3+z^3$

Published on 27 Mar 2026 - 23:40

score 100 · Answer 2 · 2019-08-05 18:34:46

100

Views

Prove that $\lim_{n \to \infty}\sqrt{n} \cdot \left(\sqrt{n+1} - \sqrt{n}\right)=\frac12$.

Published on 05 Aug 2019 - 18:34

score 1.8k · Answer 3 · 2026-03-25 07:49:06

1.8k

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Calculating the nth super-root when n is greater than 2?

Published on 25 Mar 2026 - 7:49

score 126 · Answer 4 · 2019-08-06 13:37:09

126

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Find all natural numbers $n$ such that $\sqrt{n-1}+\sqrt{n+1}$ is rational...

Published on 06 Aug 2019 - 13:37

score 108 · Answer 5 · 2019-08-08 21:02:23

108

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Why is $1=\sqrt{(-1)(-1)}=\sqrt{i^2\cdot i^2}=\sqrt{i^4}=\sqrt{\left(e^{i\frac{\pi}{2}}\right)^4}=\sqrt{e^{i2\pi}}=e^{i\pi}=-1$ wrong?

Published on 08 Aug 2019 - 21:02

score 107 · Answer 6 · 2026-03-28 03:53:06

107

Views

Evaluating $\lim_{x \to 2}\frac{\sqrt{3x-5}-\sqrt[3]{x-1}}{x-2}$

Published on 28 Mar 2026 - 3:53

score 254 · Answer 7 · 2026-03-28 01:04:51

254

Views

When is the Galois group of a quintic not $S_5$ if we use this particular method?

Published on 28 Mar 2026 - 1:04

score 132 · Answer 8 · 2026-03-27 11:47:55

132

Views

Doubt with $\sqrt[3]{x} \ne x^{\frac{1}{3}}$

Published on 27 Mar 2026 - 11:47

score 82 · Answer 9 · 2019-08-11 16:44:55

82

Views

Find "A" in this equation.

Published on 11 Aug 2019 - 16:44

score 161 · Answer 10 · 2019-08-11 17:11:51

161

Views

Find $y$ in $\sqrt{4+(y-6)^2}+\sqrt{16+(y-3)^2}=3\cdot\sqrt{5}$

Published on 11 Aug 2019 - 17:11

score 246 · Answer 11 · 2019-08-13 04:54:49

246

Views

Simplify $ \frac{ \sqrt[3]{16} - 1}{ \sqrt[3]{27} + \sqrt[3]{4} + \sqrt[3]{2}} $

Published on 13 Aug 2019 - 4:54

score 144 · Answer 12 · 2019-08-13 11:16:12

144

Views

Simplify $\sqrt{10 + \sqrt{24} + \sqrt{40} + \sqrt{60}} $

Published on 13 Aug 2019 - 11:16

score 123 · Answer 13 · 2026-03-25 21:48:45

123

Views

$n$-th derivative of $x^\alpha$ where $\alpha = m + 1/2$

Published on 25 Mar 2026 - 21:48

score 279 · Answer 14 · 2019-08-17 20:58:19

Find value of $(\cos\frac{2\pi}{7})^ {\frac{1}{3}} + (\cos\frac{4\pi}{7})^ {\frac{1}{3}} + (\cos\frac{8\pi}{7})^ {\frac{1}{3}} $

score 115 · Answer 15 · 2019-08-18 02:40:14

115

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Solve for $x, y \in \mathbb R$: $(x^2 - 1)^2 + 3 = \dfrac{6x^5y}{x^2 + 2}, 3y - x = \sqrt{\dfrac{4x - 3x^2y - 9xy^2}{x + 3y}}$

Published on 18 Aug 2019 - 2:40

List Question

Can i factor this expression: $x^3+y^3+z^3$

Prove that $\lim_{n \to \infty}\sqrt{n} \cdot \left(\sqrt{n+1} - \sqrt{n}\right)=\frac12$.

Calculating the nth super-root when n is greater than 2?

Find all natural numbers $n$ such that $\sqrt{n-1}+\sqrt{n+1}$ is rational...

Why is $1=\sqrt{(-1)(-1)}=\sqrt{i^2\cdot i^2}=\sqrt{i^4}=\sqrt{\left(e^{i\frac{\pi}{2}}\right)^4}=\sqrt{e^{i2\pi}}=e^{i\pi}=-1$ wrong?

Evaluating $\lim_{x \to 2}\frac{\sqrt{3x-5}-\sqrt[3]{x-1}}{x-2}$

When is the Galois group of a quintic not $S_5$ if we use this particular method?

Doubt with $\sqrt[3]{x} \ne x^{\frac{1}{3}}$

Find "A" in this equation.

Find $y$ in $\sqrt{4+(y-6)^2}+\sqrt{16+(y-3)^2}=3\cdot\sqrt{5}$

Simplify $ \frac{ \sqrt[3]{16} - 1}{ \sqrt[3]{27} + \sqrt[3]{4} + \sqrt[3]{2}} $

Simplify $\sqrt{10 + \sqrt{24} + \sqrt{40} + \sqrt{60}} $

$n$-th derivative of $x^\alpha$ where $\alpha = m + 1/2$

Find value of $(\cos\frac{2\pi}{7})^ {\frac{1}{3}} + (\cos\frac{4\pi}{7})^ {\frac{1}{3}} + (\cos\frac{8\pi}{7})^ {\frac{1}{3}} $

Solve for $x, y \in \mathbb R$: $(x^2 - 1)^2 + 3 = \dfrac{6x^5y}{x^2 + 2}, 3y - x = \sqrt{\dfrac{4x - 3x^2y - 9xy^2}{x + 3y}}$

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