Question

How to simplify fractions involving surds? $\frac{(\sqrt{θ^2+1})(2θ)-(θ^2-1)(\frac{θ}{\sqrt{θ^2+1}})}{θ^2+1}$

score 46 · Answer 1 · 2026-03-28 11:44:19

46

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How to simplify fractions involving surds? $\frac{(\sqrt{θ^2+1})(2θ)-(θ^2-1)(\frac{θ}{\sqrt{θ^2+1}})}{θ^2+1}$

Published on 28 Mar 2026 - 11:44

score 32 · Answer 2 · 2020-03-01 20:51:25

32

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problem in linear equation

Published on 01 Mar 2020 - 20:51

score 76 · Answer 3 · 2020-03-01 23:04:45

76

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Prove that $\frac{\sum \sqrt{xy}}{\sqrt{xyz}}-2(\sum \sqrt{x})\ge \sum \frac{\sqrt{xy}}{y}$

Published on 01 Mar 2020 - 23:04

score 90 · Answer 4 · 2020-03-02 16:26:13

90

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Find $a,b$ and $c$ if $(1+\sqrt[3]{2})^{-1}$ in the form of $a+b\sqrt[3]{2}+c\sqrt[3]{2^2}$

Published on 02 Mar 2020 - 16:26

score 139 · Answer 5 · 2026-03-29 19:31:20

139

Views

What is $\sqrt{x^2}$?

Published on 29 Mar 2026 - 19:31

score 133 · Answer 6 · 2026-03-26 16:23:09

133

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A relation between $3-\sqrt 5$ and $\sqrt 5-1$

Published on 26 Mar 2026 - 16:23

score 77 · Answer 7 · 2026-03-29 23:27:02

77

Views

If $\lim_{n \to \infty} \frac{a_{n+1}}{na_n}=a$ , then $\lim_{n \to \infty}[n(\frac{{a_{n+1}}^{\frac{1}{n}}}{n+1}-\frac{{a_{n}}^{\frac{1}{n}}}{n})]=0$

Published on 29 Mar 2026 - 23:27

score 90 · Answer 8 · 2020-03-09 15:51:49

90

Views

Square root and cube root equation $\sqrt[3]{x^6+7x^3}+(x-1)(x+1)=\sqrt{x^4+8x}-1$

Published on 09 Mar 2020 - 15:51

score 67 · Answer 9 · 2020-03-10 03:10:33

67

Views

Is ${(-1)}^{\frac{1}{6}}=i$?

Published on 10 Mar 2020 - 3:10

score 41 · Answer 10 · 2020-03-12 00:45:16

41

Views

Simplifying a Radical with Addition?

Published on 12 Mar 2020 - 0:45

score 71 · Answer 11 · 2020-03-15 17:48:32

71

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How to take the integral of a function with trigonometry?

Published on 15 Mar 2020 - 17:48

score 241 · Answer 12 · 2020-03-16 13:44:30

241

Views

Manual square root method explained

Published on 16 Mar 2020 - 13:44

score 70 · Answer 13 · 2026-03-26 01:07:23

70

Views

Using conjugates to solve indetermination on limit with cubic root

Published on 26 Mar 2026 - 1:07

score 84 · Answer 14 · 2026-03-25 09:43:08

84

Views

Inequality $\sqrt{\frac{(ab)^2+(bc)^2+(ca)^2}{a^4+b^4+c^4}}\Big(\sum_{cyc}\frac{a^2}{7a+5b}\Big)+\frac{(a-b)^2}{12}\leq \frac{1}{12}$

Published on 25 Mar 2026 - 9:43

score 40 · Answer 15 · 2020-03-19 06:17:55

40

Views

Double Summation over inverse square roots

Published on 19 Mar 2020 - 6:17

List Question

How to simplify fractions involving surds? $\frac{(\sqrt{θ^2+1})(2θ)-(θ^2-1)(\frac{θ}{\sqrt{θ^2+1}})}{θ^2+1}$

problem in linear equation

Prove that $\frac{\sum \sqrt{xy}}{\sqrt{xyz}}-2(\sum \sqrt{x})\ge \sum \frac{\sqrt{xy}}{y}$

Find $a,b$ and $c$ if $(1+\sqrt[3]{2})^{-1}$ in the form of $a+b\sqrt[3]{2}+c\sqrt[3]{2^2}$

What is $\sqrt{x^2}$?

A relation between $3-\sqrt 5$ and $\sqrt 5-1$

If $\lim_{n \to \infty} \frac{a_{n+1}}{na_n}=a$ , then $\lim_{n \to \infty}[n(\frac{{a_{n+1}}^{\frac{1}{n}}}{n+1}-\frac{{a_{n}}^{\frac{1}{n}}}{n})]=0$

Square root and cube root equation $\sqrt[3]{x^6+7x^3}+(x-1)(x+1)=\sqrt{x^4+8x}-1$

Is ${(-1)}^{\frac{1}{6}}=i$?

Simplifying a Radical with Addition?

How to take the integral of a function with trigonometry?

Manual square root method explained

Using conjugates to solve indetermination on limit with cubic root

Inequality $\sqrt{\frac{(ab)^2+(bc)^2+(ca)^2}{a^4+b^4+c^4}}\Big(\sum_{cyc}\frac{a^2}{7a+5b}\Big)+\frac{(a-b)^2}{12}\leq \frac{1}{12}$

Double Summation over inverse square roots

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