Question

How can $\sqrt{x} < 9 = [0,9)$?

score 74 · Answer 1 · 2020-06-03 22:45:27

74

Views

How can $\sqrt{x} < 9 = [0,9)$?

Published on 03 Jun 2020 - 22:45

score 234 · Answer 2 · 2026-03-28 15:21:30

234

Views

Prove that $\frac{1}{\sqrt[3]2}=\sqrt{\frac 5{\sqrt[3]4}-1}-\sqrt{(3-\sqrt[3]2)(\sqrt[3]2-1)}$

Published on 28 Mar 2026 - 15:21

score 172 · Answer 3 · 2020-06-06 01:58:30

172

Views

Solve $\sqrt{x^2+8x+7}+\sqrt{x^2+3x+2}=\sqrt{6x^2+19x+13}$

Published on 06 Jun 2020 - 1:58

score 74 · Answer 4 · 2020-06-08 16:16:43

74

Views

Evaluate $\int_{1}^{2}\frac{x^5\:dx}{\sqrt[3]{3x+x^5}}$

Published on 08 Jun 2020 - 16:16

score 81 · Answer 5 · 2026-03-30 05:28:17

81

Views

Why $\frac{|f(x)-f(x_0)|}{|\sqrt{f(x)}+\sqrt{f(x_0)}|}\leq |f(x)-f(x_0)|$ is considered true in an SE answer?

Published on 30 Mar 2026 - 5:28

score 69 · Answer 6 · 2020-06-10 12:16:56

69

Views

How to solve such equations: $z^4 = -4$, $z \in \mathbb{C}$?

Published on 10 Jun 2020 - 12:16

score 196 · Answer 7 · 2026-03-28 20:54:27

196

Views

When is $\mathbb{Q}(\sqrt{2+\sqrt{2+\sqrt{2 \ldots}}})$ Galois?

Published on 28 Mar 2026 - 20:54

score 66 · Answer 8 · 2020-06-13 07:56:00

66

Views

Help getting the result $\sqrt{n}-\sqrt{n-\frac{1}{4}}\approx\frac{1}{8\sqrt{n-\frac{1}{8}}}$

Published on 13 Jun 2020 - 7:56

score 56 · Answer 9 · 2026-04-01 23:07:15

56

Views

How to make inverse to work here?

Published on 01 Apr 2026 - 23:07

score 417 · Answer 10 · 2020-06-15 21:25:04

417

Views

Solving the system $x\sqrt{y} + y\sqrt{x} = 30$, $x\sqrt{x} + y\sqrt{y} = 35$

Published on 15 Jun 2020 - 21:25

score 1.5k · Answer 11 · 2026-03-29 20:02:28

1.5k

Views

Help to understand algorithm for finding square root?

Published on 29 Mar 2026 - 20:02

score 92 · Answer 12 · 2020-06-17 23:27:28

92

Views

Simplification of $\sqrt{2\zeta^2-1+2\zeta\sqrt{\zeta^2-1}}+\sqrt{2\zeta^2-1-2\zeta\sqrt{\zeta^2-1}}$

Published on 17 Jun 2020 - 23:27

score 268 · Answer 13 · 2026-03-30 07:07:53

268

Views

Find integers $1+\sqrt2+\sqrt3+\sqrt6=\sqrt{a+\sqrt{b+\sqrt{c+\sqrt{d}}}}$

Published on 30 Mar 2026 - 7:07

score 1.6k · Answer 14 · 2026-03-25 12:45:29

1.6k

Views

Square Root as a multi-valued function

Published on 25 Mar 2026 - 12:45

score 112 · Answer 15 · 2026-03-30 13:37:33

112

Views

What is wrong with $x=x^{2/2}=\sqrt {x^2}=\lvert x\rvert$

Published on 30 Mar 2026 - 13:37

List Question

How can $\sqrt{x} < 9 = [0,9)$?

Prove that $\frac{1}{\sqrt[3]2}=\sqrt{\frac 5{\sqrt[3]4}-1}-\sqrt{(3-\sqrt[3]2)(\sqrt[3]2-1)}$

Solve $\sqrt{x^2+8x+7}+\sqrt{x^2+3x+2}=\sqrt{6x^2+19x+13}$

Evaluate $\int_{1}^{2}\frac{x^5\:dx}{\sqrt[3]{3x+x^5}}$

Why $\frac{|f(x)-f(x_0)|}{|\sqrt{f(x)}+\sqrt{f(x_0)}|}\leq |f(x)-f(x_0)|$ is considered true in an SE answer?

How to solve such equations: $z^4 = -4$, $z \in \mathbb{C}$?

When is $\mathbb{Q}(\sqrt{2+\sqrt{2+\sqrt{2 \ldots}}})$ Galois?

Help getting the result $\sqrt{n}-\sqrt{n-\frac{1}{4}}\approx\frac{1}{8\sqrt{n-\frac{1}{8}}}$

How to make inverse to work here?

Solving the system $x\sqrt{y} + y\sqrt{x} = 30$, $x\sqrt{x} + y\sqrt{y} = 35$

Help to understand algorithm for finding square root?

Simplification of $\sqrt{2\zeta^2-1+2\zeta\sqrt{\zeta^2-1}}+\sqrt{2\zeta^2-1-2\zeta\sqrt{\zeta^2-1}}$

Find integers $1+\sqrt2+\sqrt3+\sqrt6=\sqrt{a+\sqrt{b+\sqrt{c+\sqrt{d}}}}$

Square Root as a multi-valued function

What is wrong with $x=x^{2/2}=\sqrt {x^2}=\lvert x\rvert$

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