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15
Math.TechQA.Club
2014-10-24 02:18:47
80
Views
Repeated substitution gone wrong
Published on
24 Oct 2014 - 2:18
#recurrence-relations
68
Views
Solving inhomogenous first order difference equation (recurrence relation)
Published on
24 Oct 2014 - 18:59
#probability
#recurrence-relations
591
Views
Recurrence Relation Theta bound
Published on
25 Oct 2014 - 8:48
#recurrence-relations
747
Views
Solving $ax_{n+1}+bx_n+cx_{n-1}=0$
Published on
25 Oct 2014 - 13:45
#recurrence-relations
100
Views
Proving that $\lim\limits_{n \to \infty} \frac{E_{n+1}}{E_n}=2^{-2/3}$
Published on
25 Oct 2014 - 14:11
#sequences-and-series
#numerical-methods
#recurrence-relations
97
Views
Find all solutions of recurrence relation
Published on
25 Oct 2014 - 15:15
#recurrence-relations
2.5k
Views
General solution of recurrence relation if two equal roots
Published on
25 Oct 2014 - 16:37
#recurrence-relations
69
Views
Show that a solution is the general solution.
Published on
25 Oct 2014 - 17:20
#recurrence-relations
1.8k
Views
How to give a good guess to the recurrence relation problem
Published on
26 Mar 2026 - 21:35
#discrete-mathematics
#recurrence-relations
#recursive-algorithms
182
Views
Prove that the sequence $a_{n+1}=\sqrt{2a_n+3},$ $a_1=1$, is bounded.
Published on
25 Oct 2014 - 23:18
#calculus
#real-analysis
#sequences-and-series
#recurrence-relations
107
Views
Validity of approximating a difference equation with a differential equation
Published on
26 Oct 2014 - 0:29
#ordinary-differential-equations
#partial-differential-equations
#taylor-expansion
#recurrence-relations
95
Views
Difference equation, special solution
Published on
26 Oct 2014 - 14:16
#recurrence-relations
71
Views
Given: $a_{1} =1 $ and $a_{n+1}=0.5(a_{n}+x/a_{n})$ How to prove that $\lim_{n \to \infty}a_{n}=\sqrt{x}$?
Published on
26 Oct 2014 - 16:40
#limits
#recurrence-relations
33
Views
Complexities of Recurrences in the form $t(n) = t(\alpha n) + t(\beta n) + cn$
Published on
28 Mar 2026 - 9:34
#recurrence-relations
#recursion
175
Views
Difference Equation, verify expression is solution to the equation
Published on
27 Oct 2014 - 0:04
#probability
#recurrence-relations
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