Question

Why does a partially ordered set need to be reflexive?

score 902 · Answer 1 · 2018-08-26 15:51:31

902

Views

Why does a partially ordered set need to be reflexive?

Published on 26 Aug 2018 - 15:51

score 591 · Answer 2 · 2018-08-26 16:03:33

591

Views

Let $F$ Be the Set of All Functions $f : \mathbb{R} \to \mathbb{R}$. Prove That $\preceq$ Is a Partial Order.

Published on 26 Aug 2018 - 16:03

score 3.6k · Answer 3 · 2018-08-26 18:51:55

3.6k

Views

Divisibility Relation On the Set $S = \{ 2, 6, 7, 14, 15, 30, 70, 105, 210 \}$: Hasse Diagram, Maximal, Minimal Elements, Greatest, Least elements

Published on 26 Aug 2018 - 18:51

score 90 · Answer 4 · 2018-08-27 10:33:17

90

Views

Let $R$ be a relation defined on $A . \ R^{\left(0 \right)} = Id_{A}, R^{*} = \bigcup _{\left(n\in \mathbb{N} \right)} R^{\left(n \right)}$

Published on 27 Aug 2018 - 10:33

score 38 · Answer 5 · 2018-08-27 14:49:46

38

Views

What is a relation $R$ called for which $\forall x,y,z: \neg (x R y \wedge y R z)$?

Published on 27 Aug 2018 - 14:49

score 120 · Answer 6 · 2018-08-29 07:56:06

120

Views

To draw the graph or explain why the relationship cannot be represented by a graph.

Published on 29 Aug 2018 - 7:56

score 61 · Answer 7 · 2026-03-23 07:54:41

61

Views

Finding equivalence classes under a relation

Published on 23 Mar 2026 - 7:54

score 41 · Answer 8 · 2018-09-02 12:56:00

41

Views

Prove: $ \left\langle \preccurlyeq,P_{\aleph_{0}}(\mathbb{N})\right\rangle $ is a Partially ordered set

Published on 02 Sep 2018 - 12:56

score 58 · Answer 9 · 2018-09-03 08:49:10

58

Views

Prove/disprove: there's a max element on the order $\leq \ $,as $ \ A\leq B; \ $ if $ \ \forall b_1,b_2\in B\to(b_1<b_2 \to|[b_1,b_2]\cap A|\geq2)$

Published on 03 Sep 2018 - 8:49

score 608 · Answer 10 · 2018-09-03 21:47:24

608

Views

Relation that is acyclic and complete but not transitive

Published on 03 Sep 2018 - 21:47

score 3k · Answer 11 · 2018-09-05 01:04:57

3k

Views

Can a relation be transitive when it is symmetric but not reflexive?

Published on 05 Sep 2018 - 1:04

score 73 · Answer 12 · 2026-03-22 02:37:55

73

Views

Subsets of an equivalence relation- terminology question

Published on 22 Mar 2026 - 2:37

score 122 · Answer 13 · 2026-03-25 17:40:15

122

Views

Is there any unique function $c=f(a, b)$ such that if I know only $c$, I can deduce unique $a$ and $b$ from it?

Published on 25 Mar 2026 - 17:40

score 438 · Answer 14 · 2026-03-22 06:44:32

438

Views

Equivalence relations S on A with R being a relation on A with 4 equivalence classes.

Published on 22 Mar 2026 - 6:44

score 321 · Answer 15 · 2018-09-12 09:42:37

321

Views

proof of a partition

Published on 12 Sep 2018 - 9:42

List Question

Why does a partially ordered set need to be reflexive?

Let $F$ Be the Set of All Functions $f : \mathbb{R} \to \mathbb{R}$. Prove That $\preceq$ Is a Partial Order.

Divisibility Relation On the Set $S = \{ 2, 6, 7, 14, 15, 30, 70, 105, 210 \}$: Hasse Diagram, Maximal, Minimal Elements, Greatest, Least elements

Let $R$ be a relation defined on $A . \ R^{\left(0 \right)} = Id_{A}, R^{*} = \bigcup _{\left(n\in \mathbb{N} \right)} R^{\left(n \right)}$

What is a relation $R$ called for which $\forall x,y,z: \neg (x R y \wedge y R z)$?

To draw the graph or explain why the relationship cannot be represented by a graph.

Finding equivalence classes under a relation

Prove: $ \left\langle \preccurlyeq,P_{\aleph_{0}}(\mathbb{N})\right\rangle $ is a Partially ordered set

Prove/disprove: there's a max element on the order $\leq \ $,as $ \ A\leq B; \ $ if $ \ \forall b_1,b_2\in B\to(b_1<b_2 \to|[b_1,b_2]\cap A|\geq2)$

Relation that is acyclic and complete but not transitive

Can a relation be transitive when it is symmetric but not reflexive?

Subsets of an equivalence relation- terminology question

Is there any unique function $c=f(a, b)$ such that if I know only $c$, I can deduce unique $a$ and $b$ from it?

Equivalence relations S on A with R being a relation on A with 4 equivalence classes.

proof of a partition

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