Question

Is the argument of the Riemann zeta function bounded in the root free region on RH?

score 152 · Answer 1 · 2018-06-17 21:21:32

152

Views

Is the argument of the Riemann zeta function bounded in the root free region on RH?

Published on 17 Jun 2018 - 21:21

score 53 · Answer 2 · 2018-06-18 20:32:48

53

Views

Series of Natural Logarithms Raised to Powers

Published on 18 Jun 2018 - 20:32

score 409 · Answer 3 · 2018-06-21 12:29:06

409

Views

Trying to prove that $\zeta(3)=\frac{5}{2} \sum_{k=1}^{\infty}{\frac{ (-1)^{k-1}} {\binom {2k}{k}k^{3}}}$

Published on 21 Jun 2018 - 12:29

score 844 · Answer 4 · 2018-06-21 14:25:00

844

Views

A new proof that $\zeta(2n+1)$ for integer $n>1$ is irrational?

Published on 21 Jun 2018 - 14:25

score 71 · Answer 5 · 2018-06-23 02:52:49

71

Views

Euler product on congruence classes

Published on 23 Jun 2018 - 2:52

score 74 · Answer 6 · 2026-03-26 14:18:41

74

Views

Product of Zeta function

Published on 26 Mar 2026 - 14:18

score 295 · Answer 7 · 2018-06-27 14:07:55

295

Views

Do similar expressions exist for odd zeta values other than $3$?

Published on 27 Jun 2018 - 14:07

score 105 · Answer 8 · 2026-03-25 06:06:35

105

Views

Is this expression of the Riemann zeta function as a Mellin transform true for $\Im\{s\}\neq 0$?

Published on 25 Mar 2026 - 6:06

score 107 · Answer 9 · 2018-06-29 16:42:05

107

Views

Binomial coefficient identity found in Apéry's theorem

Published on 29 Jun 2018 - 16:42

score 324 · Answer 10 · 2018-07-02 18:50:28

324

Views

Absolute maximum of Riemann Zeta Function

Published on 02 Jul 2018 - 18:50

score 3.9k · Answer 11 · 2026-03-25 11:16:38

3.9k

Views

How to apply the Abel-summation on this series: $\sum_{k=1}^{\infty}((-1)^{k-1} \cdot k) = 1 - 2 + 3 - 4 + ...$

Published on 25 Mar 2026 - 11:16

score 162 · Answer 12 · 2026-03-22 05:53:01

162

Views

Infinite/Recursive Cesàro Summation of $\zeta(1)$

Published on 22 Mar 2026 - 5:53

score 98 · Answer 13 · 2026-03-25 13:04:40

98

Views

Is there a closed-form expression for this integral?

Published on 25 Mar 2026 - 13:04

score 1.7k · Answer 14 · 2018-07-08 18:52:29

1.7k

Views

What are the "moments" of the Riemann zeta function?

Published on 08 Jul 2018 - 18:52

score 92 · Answer 15 · 2026-03-26 01:12:43

92

Views

Does $z (s) = \int_0^s \zeta \left( \frac{1}{2} + i t \right) d t = s + \sum_{n = 2}^{\infty} \frac{i (n^{- i s} - 1)}{\ln (n) \sqrt{n}}$ converge?

Published on 26 Mar 2026 - 1:12

List Question

Is the argument of the Riemann zeta function bounded in the root free region on RH?

Series of Natural Logarithms Raised to Powers

Trying to prove that $\zeta(3)=\frac{5}{2} \sum_{k=1}^{\infty}{\frac{ (-1)^{k-1}} {\binom {2k}{k}k^{3}}}$

A new proof that $\zeta(2n+1)$ for integer $n>1$ is irrational?

Euler product on congruence classes

Product of Zeta function

Do similar expressions exist for odd zeta values other than $3$?

Is this expression of the Riemann zeta function as a Mellin transform true for $\Im\{s\}\neq 0$?

Binomial coefficient identity found in Apéry's theorem

Absolute maximum of Riemann Zeta Function

How to apply the Abel-summation on this series: $\sum_{k=1}^{\infty}((-1)^{k-1} \cdot k) = 1 - 2 + 3 - 4 + ...$

Infinite/Recursive Cesàro Summation of $\zeta(1)$

Is there a closed-form expression for this integral?

What are the "moments" of the Riemann zeta function?

Does $z (s) = \int_0^s \zeta \left( \frac{1}{2} + i t \right) d t = s + \sum_{n = 2}^{\infty} \frac{i (n^{- i s} - 1)}{\ln (n) \sqrt{n}}$ converge?

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