Question

Image of an ideal under a surjective ring homomorphism is an ideal

score 1.6k · Answer 1 · 2026-04-14 20:05:34

1.6k

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Image of an ideal under a surjective ring homomorphism is an ideal

Published on 14 Apr 2026 - 20:05

score 96 · Answer 2 · 2026-04-15 07:15:19

96

Views

Ring homomorphisms from $\mathbb{R}$ to another unital ring $S$.

Published on 15 Apr 2026 - 7:15

score 174 · Answer 3 · 2026-04-09 14:33:15

174

Views

Showing that $\varphi:\mathbb{Z}/n\mathbb{Z}\rightarrow \mathbb{Z}/m\mathbb{Z}$ is a well-defined surjective ring homomorphism

Published on 09 Apr 2026 - 14:33

score 53 · Answer 4 · 2026-04-12 00:36:07

53

Views

$\varphi : R\rightarrow \mathbb{Z}/p\mathbb{Z},x\mapsto x+p\mathbb{Z}$ is well-defined and surjective.

Published on 12 Apr 2026 - 0:36

score 64 · Answer 5 · 2026-05-10 19:38:47

64

Views

Hom$_{i[k]}(k[G], R) \approx$ Hom$(G,R^*)$

Published on 10 May 2026 - 19:38

score 82 · Answer 6 · 2026-05-10 16:00:15

82

Views

Prove that a homomorphism is surjective

Published on 10 May 2026 - 16:00

score 27 · Answer 7 · 2026-04-11 12:00:50

27

Views

ring homomorphism natures are used to determind all mappings

Published on 11 Apr 2026 - 12:00

score 169 · Answer 8 · 2026-04-11 22:32:20

169

Views

Extension of irreducible ideal is irreducible

Published on 11 Apr 2026 - 22:32

score 58 · Answer 9 · 2026-04-16 20:22:22

58

Views

If $(A,+,\cdot)$ and $(B,+,\cdot)$ are rings and there exists a homomorphism such that $\phi:A\rightarrow B$ then $\phi(1_A)=1_B$?

Published on 16 Apr 2026 - 20:22

score 188 · Answer 10 · 2026-05-11 07:42:37

188

Views

Explicit description of the map with the nilradical as its kernel

Published on 11 May 2026 - 7:42

score 272 · Answer 11 · 2026-04-13 23:32:50

272

Views

Radical of the Extension of Ideals and The Extension of an Radical Ideals

Published on 13 Apr 2026 - 23:32

score 744 · Answer 12 · 2026-04-12 12:47:30

744

Views

Why should the kernel of a ring homomorphism be an ideal?

Published on 12 Apr 2026 - 12:47

score 97 · Answer 13 · 2026-04-15 06:10:30

97

Views

why is n divisible by 1+3i in the ring of Gauss integers?

Published on 15 Apr 2026 - 6:10

score 39 · Answer 14 · 2026-04-17 12:29:27

39

Views

Showing surjectivity of ring homomorphism

Published on 17 Apr 2026 - 12:29

score 200 · Answer 15 · 2026-05-11 05:08:02

200

Views

If $S$ is an $R$-algebra, how does $S$ being a finitely generated $R$-module imply that $S$ is a finite-type $R$-algebra?

Published on 11 May 2026 - 5:08

List Question

Image of an ideal under a surjective ring homomorphism is an ideal

Ring homomorphisms from $\mathbb{R}$ to another unital ring $S$.

Showing that $\varphi:\mathbb{Z}/n\mathbb{Z}\rightarrow \mathbb{Z}/m\mathbb{Z}$ is a well-defined surjective ring homomorphism

$\varphi : R\rightarrow \mathbb{Z}/p\mathbb{Z},x\mapsto x+p\mathbb{Z}$ is well-defined and surjective.

Hom$_{i[k]}(k[G], R) \approx$ Hom$(G,R^*)$

Prove that a homomorphism is surjective

ring homomorphism natures are used to determind all mappings

Extension of irreducible ideal is irreducible

If $(A,+,\cdot)$ and $(B,+,\cdot)$ are rings and there exists a homomorphism such that $\phi:A\rightarrow B$ then $\phi(1_A)=1_B$?

Explicit description of the map with the nilradical as its kernel

Radical of the Extension of Ideals and The Extension of an Radical Ideals

Why should the kernel of a ring homomorphism be an ideal?

why is n divisible by 1+3i in the ring of Gauss integers?

Showing surjectivity of ring homomorphism

If $S$ is an $R$-algebra, how does $S$ being a finitely generated $R$-module imply that $S$ is a finite-type $R$-algebra?

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