Question

Image of an ideal under a surjective ring homomorphism is an ideal

score 1.6k · Answer 1 · 2019-05-18 19:39:23

1.6k

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Image of an ideal under a surjective ring homomorphism is an ideal

Published on 18 May 2019 - 19:39

score 93 · Answer 2 · 2019-05-20 00:51:24

93

Views

Ring homomorphisms from $\mathbb{R}$ to another unital ring $S$.

Published on 20 May 2019 - 0:51

score 171 · Answer 3 · 2019-05-20 15:55:55

171

Views

Showing that $\varphi:\mathbb{Z}/n\mathbb{Z}\rightarrow \mathbb{Z}/m\mathbb{Z}$ is a well-defined surjective ring homomorphism

Published on 20 May 2019 - 15:55

score 50 · Answer 4 · 2019-05-21 15:41:50

50

Views

$\varphi : R\rightarrow \mathbb{Z}/p\mathbb{Z},x\mapsto x+p\mathbb{Z}$ is well-defined and surjective.

Published on 21 May 2019 - 15:41

score 61 · Answer 5 · 2026-03-25 06:05:40

61

Views

Hom$_{i[k]}(k[G], R) \approx$ Hom$(G,R^*)$

Published on 25 Mar 2026 - 6:05

score 79 · Answer 6 · 2026-03-25 07:40:48

79

Views

Prove that a homomorphism is surjective

Published on 25 Mar 2026 - 7:40

score 24 · Answer 7 · 2019-06-29 03:54:27

24

Views

ring homomorphism natures are used to determind all mappings

Published on 29 Jun 2019 - 3:54

score 166 · Answer 8 · 2019-06-29 19:12:48

166

Views

Extension of irreducible ideal is irreducible

Published on 29 Jun 2019 - 19:12

score 55 · Answer 9 · 2019-07-01 09:49:11

55

Views

If $(A,+,\cdot)$ and $(B,+,\cdot)$ are rings and there exists a homomorphism such that $\phi:A\rightarrow B$ then $\phi(1_A)=1_B$?

Published on 01 Jul 2019 - 9:49

score 184 · Answer 10 · 2019-07-02 01:19:59

184

Views

Explicit description of the map with the nilradical as its kernel

Published on 02 Jul 2019 - 1:19

score 269 · Answer 11 · 2019-07-20 20:09:41

269

Views

Radical of the Extension of Ideals and The Extension of an Radical Ideals

Published on 20 Jul 2019 - 20:09

score 741 · Answer 12 · 2019-07-21 19:33:41

741

Views

Why should the kernel of a ring homomorphism be an ideal?

Published on 21 Jul 2019 - 19:33

score 94 · Answer 13 · 2019-07-22 17:48:34

94

Views

why is n divisible by 1+3i in the ring of Gauss integers?

Published on 22 Jul 2019 - 17:48

score 35 · Answer 14 · 2019-07-23 09:51:37

35

Views

Showing surjectivity of ring homomorphism

Published on 23 Jul 2019 - 9:51

score 196 · Answer 15 · 2019-07-26 22:35:18

196

Views

If $S$ is an $R$-algebra, how does $S$ being a finitely generated $R$-module imply that $S$ is a finite-type $R$-algebra?

Published on 26 Jul 2019 - 22:35

List Question

Image of an ideal under a surjective ring homomorphism is an ideal

Ring homomorphisms from $\mathbb{R}$ to another unital ring $S$.

Showing that $\varphi:\mathbb{Z}/n\mathbb{Z}\rightarrow \mathbb{Z}/m\mathbb{Z}$ is a well-defined surjective ring homomorphism

$\varphi : R\rightarrow \mathbb{Z}/p\mathbb{Z},x\mapsto x+p\mathbb{Z}$ is well-defined and surjective.

Hom$_{i[k]}(k[G], R) \approx$ Hom$(G,R^*)$

Prove that a homomorphism is surjective

ring homomorphism natures are used to determind all mappings

Extension of irreducible ideal is irreducible

If $(A,+,\cdot)$ and $(B,+,\cdot)$ are rings and there exists a homomorphism such that $\phi:A\rightarrow B$ then $\phi(1_A)=1_B$?

Explicit description of the map with the nilradical as its kernel

Radical of the Extension of Ideals and The Extension of an Radical Ideals

Why should the kernel of a ring homomorphism be an ideal?

why is n divisible by 1+3i in the ring of Gauss integers?

Showing surjectivity of ring homomorphism

If $S$ is an $R$-algebra, how does $S$ being a finitely generated $R$-module imply that $S$ is a finite-type $R$-algebra?

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