Question

$\mathbb{Z}$-filtration on $\mathbb{C}(t)$

score 22 · Answer 1 · 2026-03-26 01:01:18

22

Views

$\mathbb{Z}$-filtration on $\mathbb{C}(t)$

Published on 26 Mar 2026 - 1:01

score 105 · Answer 2 · 2026-03-27 13:25:35

105

Views

Find all irreducible monic polynomials of degrees $2$ in $\Bbb{Z}_{4}[x]$.

Published on 27 Mar 2026 - 13:25

score 714 · Answer 3 · 2026-04-11 14:43:08

714

Views

Ring of integers of quadratic field extension, every element with prime norm is a prime

Published on 11 Apr 2026 - 14:43

score 253 · Answer 4 · 2026-04-03 10:38:34

253

Views

Proving $M = 0 \iff aM = M$ if $a \in R$ is nilpotent and $M$ is an $R$-module for commutative $R$

Published on 03 Apr 2026 - 10:38

score 67 · Answer 5 · 2026-04-11 02:26:54

67

Views

What is the length of a semisimple module, if defined?

Published on 11 Apr 2026 - 2:26

score 85 · Answer 6 · 2026-03-28 14:56:51

85

Views

Find the inverse in $F = \frac{\Bbb{Z}_{7}[x]}{g(x)}$ of a polynomial $p(x)$

Published on 28 Mar 2026 - 14:56

score 115 · Answer 7 · 2026-04-10 16:16:53

115

Views

Abelian groups that arise as unit groups of discrete valuation rings

Published on 10 Apr 2026 - 16:16

score 144 · Answer 8 · 2026-04-11 13:39:01

144

Views

Geometrically interpreting quotient rings

Published on 11 Apr 2026 - 13:39

score 508 · Answer 9 · 2026-04-11 02:22:26

508

Views

Defining ring structure for the Rees algebra of an ideal

Published on 11 Apr 2026 - 2:22

score 87 · Answer 10 · 2019-08-08 16:03:16

87

Views

$R$ commutative, $I$ maximal w.r.t. non-finitely generated ideals, show $I$ not finitely generated.

Published on 08 Aug 2019 - 16:03

score 796 · Answer 11 · 2019-08-08 17:08:27

796

Views

Non-Noetherian one-dimensional domain with a finitely generated maximal ideal

Published on 08 Aug 2019 - 17:08

score 1.6k · Answer 12 · 2026-04-10 20:17:08

1.6k

Views

Every prime ideal in $\mathbb{Z}[x]$ is generated by at most two elements

Published on 10 Apr 2026 - 20:17

score 1.1k · Answer 13 · 2026-03-29 18:50:32

1.1k

Views

Must a ring (commutative, with 1), in which every non-zero ideal is prime, be a field?

Published on 29 Mar 2026 - 18:50

score 91 · Answer 14 · 2026-04-03 10:43:39

91

Views

If $R$ is an integral domain and $M=\langle m_1, \dots, m_k \rangle$ is an $R$-module, then the rank of $M$ is less than or equal to $k$.

Published on 03 Apr 2026 - 10:43

score 43 · Answer 15 · 2019-08-09 11:19:19

43

Views

Does the characteristic of a ring R without zero divisors 0 or prime?

Published on 09 Aug 2019 - 11:19

List Question

$\mathbb{Z}$-filtration on $\mathbb{C}(t)$

Find all irreducible monic polynomials of degrees $2$ in $\Bbb{Z}_{4}[x]$.

Ring of integers of quadratic field extension, every element with prime norm is a prime

Proving $M = 0 \iff aM = M$ if $a \in R$ is nilpotent and $M$ is an $R$-module for commutative $R$

What is the length of a semisimple module, if defined?

Find the inverse in $F = \frac{\Bbb{Z}_{7}[x]}{g(x)}$ of a polynomial $p(x)$

Abelian groups that arise as unit groups of discrete valuation rings

Geometrically interpreting quotient rings

Defining ring structure for the Rees algebra of an ideal

$R$ commutative, $I$ maximal w.r.t. non-finitely generated ideals, show $I$ not finitely generated.

Non-Noetherian one-dimensional domain with a finitely generated maximal ideal

Every prime ideal in $\mathbb{Z}[x]$ is generated by at most two elements

Must a ring (commutative, with 1), in which every non-zero ideal is prime, be a field?

If $R$ is an integral domain and $M=\langle m_1, \dots, m_k \rangle$ is an $R$-module, then the rank of $M$ is less than or equal to $k$.

Does the characteristic of a ring R without zero divisors 0 or prime?

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