Question

Show that operator is self-adjoint in $\mu L^2(\mu dv)$

score 52 · Answer 1 · 2023-05-07 11:50:21

52

Views

Show that operator is self-adjoint in $\mu L^2(\mu dv)$

Published on 07 May 2023 - 11:50

score 81 · Answer 2 · 2023-05-07 16:49:16

81

Views

$T : H \to H$ bounded self-adjoint, when is $\sup \langle Tx, x \rangle$ achieved?

Published on 07 May 2023 - 16:49

score 36 · Answer 3 · 2023-05-09 20:52:15

36

Views

Restriction of self-adjoint operator to the vectors orthogonal to a finite-dimensional subspace

Published on 09 May 2023 - 20:52

score 69 · Answer 4 · 2023-05-21 12:07:20

69

Views

If an element $b$ of a $C^*$-algebra $B$ is self-adjoint with $\delta=\|b-b^2\|<\frac14$ then there is a projection $p\in B$ with $\|b-p\|\leq2\delta$

Published on 21 May 2023 - 12:07

score 95 · Answer 5 · 2023-05-28 12:38:07

95

Views

If $f$ is a eigenfunction of $-\Delta$ in $L^2[0,1]$, is it necessarily $C^\infty$?

Published on 28 May 2023 - 12:38

score 66 · Answer 6 · 2023-05-29 16:42:29

66

Views

Assume $|u_n| =1$ for all $n$ and $\langle Tu_n, u_n\rangle \xrightarrow{n \to \infty} \alpha$. Then $\alpha u_n - Tu_n \xrightarrow{n \to \infty} 0$

Published on 29 May 2023 - 16:42

score 34 · Answer 7 · 2023-06-01 09:25:31

34

Views

Difference between time reversible and stationary distribution. "watching a movie backwards"

Published on 01 Jun 2023 - 9:25

score 30 · Answer 8 · 2023-06-02 22:53:01

30

Views

endomorphism and square root self-adjoint operator

Published on 02 Jun 2023 - 22:53

score 87 · Answer 9 · 2023-06-02 23:40:06

87

Views

endomorphism and self adjoint operators and isometry

Published on 02 Jun 2023 - 23:40

score 47 · Answer 10 · 2026-03-25 18:45:02

47

Views

is this (unbounded) operator normal?

Published on 25 Mar 2026 - 18:45

score 34 · Answer 11 · 2023-06-05 01:35:07

34

Views

self-adjoint projection

Published on 05 Jun 2023 - 1:35

score 62 · Answer 12 · 2026-03-25 19:02:28

62

Views

Spectral decomposition of a normal operator: non-distinct eigenvalues

Published on 25 Mar 2026 - 19:02

score 42 · Answer 13 · 2023-06-18 11:45:16

42

Views

Does $A^*$ being self-adjoint imply that $A$ is self adjoint?

Published on 18 Jun 2023 - 11:45

score 135 · Answer 14 · 2023-06-18 20:47:03

135

Views

Prove that matrix is Hermitian iff it's equal to its adjoint with general hermitian inner products

Published on 18 Jun 2023 - 20:47

score 55 · Answer 15 · 2023-06-21 23:22:16

55

Views

Commuting self adjoint operator exercise.

Published on 21 Jun 2023 - 23:22

List Question

Show that operator is self-adjoint in $\mu L^2(\mu dv)$

$T : H \to H$ bounded self-adjoint, when is $\sup \langle Tx, x \rangle$ achieved?

Restriction of self-adjoint operator to the vectors orthogonal to a finite-dimensional subspace

If an element $b$ of a $C^*$-algebra $B$ is self-adjoint with $\delta=\|b-b^2\|<\frac14$ then there is a projection $p\in B$ with $\|b-p\|\leq2\delta$

If $f$ is a eigenfunction of $-\Delta$ in $L^2[0,1]$, is it necessarily $C^\infty$?

Assume $|u_n| =1$ for all $n$ and $\langle Tu_n, u_n\rangle \xrightarrow{n \to \infty} \alpha$. Then $\alpha u_n - Tu_n \xrightarrow{n \to \infty} 0$

Difference between time reversible and stationary distribution. "watching a movie backwards"

endomorphism and square root self-adjoint operator

endomorphism and self adjoint operators and isometry

is this (unbounded) operator normal?

self-adjoint projection

Spectral decomposition of a normal operator: non-distinct eigenvalues

Does $A^*$ being self-adjoint imply that $A$ is self adjoint?

Prove that matrix is Hermitian iff it's equal to its adjoint with general hermitian inner products

Commuting self adjoint operator exercise.

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