Question

Convergence of self-adjoint operators with converging spectra

score 33 · Answer 1 · 2026-03-25 20:15:24

33

Views

Convergence of self-adjoint operators with converging spectra

Published on 25 Mar 2026 - 20:15

score 39 · Answer 2 · 2026-03-26 04:31:26

39

Views

Proof that an operator is self-adjoint if and only if its matrix is self-adjoint

Published on 26 Mar 2026 - 4:31

score 75 · Answer 3 · 2023-09-07 14:25:15

75

Views

About the strong commutativity of unbounded self-adjoint operators?

Published on 07 Sep 2023 - 14:25

score 45 · Answer 4 · 2023-09-12 17:54:37

45

Views

If $T$ is self-adjoint and $\alpha \in \mathbb{R}$, show that $\alpha \langle Tv,v \rangle \geq -|\alpha| \lVert Tv \rVert \lVert v \rVert$

Published on 12 Sep 2023 - 17:54

score 62 · Answer 5 · 2026-02-23 17:28:17

62

Views

When is the image of the functional calculus of a self-adjoint operator also self-adjoint?

Published on 23 Feb 2026 - 17:28

score 34 · Answer 6 · 2023-10-04 20:08:08

34

Views

Proving Self-Adjointness and Diagonalizability of a Linear Operator on Polynomials

Published on 04 Oct 2023 - 20:08

score 42 · Answer 7 · 2023-10-07 13:57:46

42

Views

How to calculate the trace of a semigroup?

Published on 07 Oct 2023 - 13:57

score 95 · Answer 8 · 2023-10-10 13:41:33

95

Views

Spectral theorem and invertible operators

Published on 10 Oct 2023 - 13:41

score 66 · Answer 9 · 2023-10-15 13:13:20

66

Views

is it an equivalent definition of the Schwartz Space? all real smooth function that $ f^{(k)}(\infty)=0=f^{(k)}(-\infty)$

Published on 15 Oct 2023 - 13:13

score 46 · Answer 10 · 2023-10-23 09:50:25

46

Views

Powers of operators and spectral gap

Published on 23 Oct 2023 - 9:50

score 173 · Answer 11 · 2026-03-25 20:11:53

173

Views

Reed and Simon, Fourier Analysis and Self-Adjointness, second corollary to Theorem X.$25$: how to show that $D(A^2)$ is dense in $D(A)$ for its norm?

Published on 25 Mar 2026 - 20:11

score 91 · Answer 12 · 2023-11-12 20:16:12

91

Views

Laplace-Beltrami operator self-adjoint in context of Markov processes and their infinitesimal generators

Published on 12 Nov 2023 - 20:16

score 25 · Answer 13 · 2023-11-27 02:12:09

25

Views

Property of being Fredholm after applying the Helmholtz operator

Published on 27 Nov 2023 - 2:12

score 37 · Answer 14 · 2023-11-29 13:53:20

37

Views

Spectral theory simply implies that two commuting self-adjoint operators are functional calculi of a third self-adjoint operator?

Published on 29 Nov 2023 - 13:53

score 26 · Answer 15 · 2023-11-29 16:19:39

26

Views

Semigroup solving Schrödinger equation weakly is a unitary group

Published on 29 Nov 2023 - 16:19

List Question

Convergence of self-adjoint operators with converging spectra

Proof that an operator is self-adjoint if and only if its matrix is self-adjoint

About the strong commutativity of unbounded self-adjoint operators?

If $T$ is self-adjoint and $\alpha \in \mathbb{R}$, show that $\alpha \langle Tv,v \rangle \geq -|\alpha| \lVert Tv \rVert \lVert v \rVert$

When is the image of the functional calculus of a self-adjoint operator also self-adjoint?

Proving Self-Adjointness and Diagonalizability of a Linear Operator on Polynomials

How to calculate the trace of a semigroup?

Spectral theorem and invertible operators

is it an equivalent definition of the Schwartz Space? all real smooth function that $ f^{(k)}(\infty)=0=f^{(k)}(-\infty)$

Powers of operators and spectral gap

Reed and Simon, Fourier Analysis and Self-Adjointness, second corollary to Theorem X.$25$: how to show that $D(A^2)$ is dense in $D(A)$ for its norm?

Laplace-Beltrami operator self-adjoint in context of Markov processes and their infinitesimal generators

Property of being Fredholm after applying the Helmholtz operator

Spectral theory simply implies that two commuting self-adjoint operators are functional calculi of a third self-adjoint operator?

Semigroup solving Schrödinger equation weakly is a unitary group

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