List questions from self-adjoint-operators

Published on 23 Feb 2026 - 21:15

246

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If a operator $A$ in Hilbert space is positive then $A$ is self-adjoint?

Published on 02 Apr 2020 - 1:10

94

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About invariant subspaces of resolvent operators

Published on 21 Apr 2020 - 11:40

175

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Stone formula and joint spectral measures for commuting operators

Published on 21 Apr 2020 - 14:41

39

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If $p^{2}=p^{}=p$ and $pa^{}a=paa^{}=0$, then $a^{}p+pa=0$.

Published on 25 Mar 2026 - 9:43

49

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If $P,Q$ orthogonal projections on $H$ and $T\colon H\to H$ extension of Hilbert isomorphism $S\colon P(H)\to Q(H)$, then $Q=TT^{*}$.

Published on 22 Apr 2020 - 16:10

144

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If $P$ is a projection and $T$ is positive operator such that $P\leq T$, then why $P(H)\subset\sqrt{T}(H)$?

Published on 24 Apr 2020 - 17:37

219

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inequality for positive contraction operator

Published on 26 Apr 2020 - 7:10

437

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Hilbert space self adjoint and idempotent

Published on 27 Apr 2020 - 2:55

46

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Semi-positivity of an Hermitian matrix

Published on 29 Apr 2020 - 0:47

66

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prove $Ax_n - \lambda x_n \to 0$

Published on 29 Apr 2020 - 19:43

113

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Tail of increasing convergent net of self-adjoint operators is bounded

Published on 23 Feb 2026 - 14:09

139

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Self-adjoint operator as composition of bounded and self-adjoint

Published on 15 May 2020 - 11:38

483

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Is self-adjoint operator necessarily linear?

Published on 16 May 2020 - 11:57

66

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If $S$ and $T$ are distinct self-adjoint operators on $H$ such that $S\leq T$, can we conclude that $\langle Sx,x\rangle<\langle Tx,x\rangle$?

Published on 16 May 2020 - 12:47

List Question

If a operator $L$ in a Hilbert space is self-adjoint, then $L$ is coercive?

If a operator $A$ in Hilbert space is positive then $A$ is self-adjoint?

About invariant subspaces of resolvent operators

Stone formula and joint spectral measures for commuting operators

If $p^{2}=p^{}=p$ and $pa^{}a=paa^{}=0$, then $a^{}p+pa=0$.

If $P,Q$ orthogonal projections on $H$ and $T\colon H\to H$ extension of Hilbert isomorphism $S\colon P(H)\to Q(H)$, then $Q=TT^{*}$.

If $P$ is a projection and $T$ is positive operator such that $P\leq T$, then why $P(H)\subset\sqrt{T}(H)$?

inequality for positive contraction operator

Hilbert space self adjoint and idempotent

Semi-positivity of an Hermitian matrix

prove $Ax_n - \lambda x_n \to 0$

Tail of increasing convergent net of self-adjoint operators is bounded

Self-adjoint operator as composition of bounded and self-adjoint

Is self-adjoint operator necessarily linear?

If $S$ and $T$ are distinct self-adjoint operators on $H$ such that $S\leq T$, can we conclude that $\langle Sx,x\rangle<\langle Tx,x\rangle$?

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