Question

Sheaf cohomology is independent of the flasque resolution

score 764 · Answer 1 · 2026-03-28 06:59:55

764

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Sheaf cohomology is independent of the flasque resolution

Published on 28 Mar 2026 - 6:59

score 247 · Answer 2 · 2026-02-23 10:49:50

247

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Relation between $\mathcal{O}_Y\rightarrow f_*\mathcal{O}_{X}$ and $f^{-1}\mathcal{O}_Y\rightarrow \mathcal{O}_X$ being epimorphism/monomorphism.

Published on 23 Feb 2026 - 10:49

score 1.3k · Answer 3 · 2017-11-17 12:01:41

1.3k

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Global Section as Sheaf Morphism

Published on 17 Nov 2017 - 12:01

score 71 · Answer 4 · 2017-11-18 17:33:27

71

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When is $Ind(\mathcal{C})$ equivalent to $PSh(\mathcal{C})$?

Published on 18 Nov 2017 - 17:33

score 74 · Answer 5 · 2017-11-19 12:21:05

74

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On morphisms of $\mathcal {O}_X $ modules

Published on 19 Nov 2017 - 12:21

score 221 · Answer 6 · 2017-11-19 17:51:54

221

Views

Sheaves of analytic functions were once called multi-valued functions.

Published on 19 Nov 2017 - 17:51

score 63 · Answer 7 · 2017-11-19 22:10:47

63

Views

$\mathbb{A}^1$ action on cones

Published on 19 Nov 2017 - 22:10

score 206 · Answer 8 · 2017-11-21 22:21:31

206

Views

Counterexamples to gluing complexes of sheaves

Published on 21 Nov 2017 - 22:21

score 30 · Answer 9 · 2017-11-22 15:21:56

30

Views

Gluing axiom of restriction maps between sections on closed sets

Published on 22 Nov 2017 - 15:21

score 65 · Answer 10 · 2026-02-23 12:27:53

65

Views

Ways of approaching the study of a Hausdorff space $X$ which has the structure of a complex manifold.

Published on 23 Feb 2026 - 12:27

score 175 · Answer 11 · 2026-03-28 07:05:11

175

Views

Cartier Divisor generated by Global Sections

Published on 28 Mar 2026 - 7:05

score 89 · Answer 12 · 2017-11-28 01:27:26

89

Views

Liu's Proof of Prop. 7.4.1

Published on 28 Nov 2017 - 1:27

score 83 · Answer 13 · 2017-11-30 13:13:36

83

Views

Is the presheaf defined by $U\to \operatorname{Im}(\alpha (U))$ indeed a sheaf?

Published on 30 Nov 2017 - 13:13

score 105 · Answer 14 · 2017-11-30 22:31:11

105

Views

Concrete Example to show that restriction maps in sheaves may not necessarily be restrctions.

Published on 30 Nov 2017 - 22:31

score 37 · Answer 15 · 2017-12-01 04:35:01

37

Views

$(\operatorname{Im}\alpha)(\operatorname{Spec}A)=\operatorname{Im}(\alpha(\operatorname{Spec}A))$?

Published on 01 Dec 2017 - 4:35

List Question

Sheaf cohomology is independent of the flasque resolution

Relation between $\mathcal{O}_Y\rightarrow f_*\mathcal{O}_{X}$ and $f^{-1}\mathcal{O}_Y\rightarrow \mathcal{O}_X$ being epimorphism/monomorphism.

Global Section as Sheaf Morphism

When is $Ind(\mathcal{C})$ equivalent to $PSh(\mathcal{C})$?

On morphisms of $\mathcal {O}_X $ modules

Sheaves of analytic functions were once called multi-valued functions.

$\mathbb{A}^1$ action on cones

Counterexamples to gluing complexes of sheaves

Gluing axiom of restriction maps between sections on closed sets

Ways of approaching the study of a Hausdorff space $X$ which has the structure of a complex manifold.

Cartier Divisor generated by Global Sections

Liu's Proof of Prop. 7.4.1

Is the presheaf defined by $U\to \operatorname{Im}(\alpha (U))$ indeed a sheaf?

Concrete Example to show that restriction maps in sheaves may not necessarily be restrctions.

$(\operatorname{Im}\alpha)(\operatorname{Spec}A)=\operatorname{Im}(\alpha(\operatorname{Spec}A))$?

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