List questions from simple-groups

Published on 12 Apr 2026 - 1:03

70

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$\operatorname{Aut}(G)=S$ is non-abelian simple with $\operatorname{Out}(S)>1$.

Published on 15 Apr 2026 - 22:15

89

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Is every $2$-generated simple group $\frac{3}{2}$-generated?

Published on 12 Apr 2026 - 5:30

205

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Transitivity of $\Omega$ in subspace actions

Published on 04 May 2026 - 11:32

462

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There is no simple group of order 528

Published on 15 Apr 2026 - 11:45

74

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Elements in non-Abelian simple Groups.

Published on 15 Apr 2026 - 5:49

117

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Are free groups residually simple?

Published on 12 Apr 2026 - 16:47

66

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Suzuki and solvability of finite groups

Published on 14 Apr 2026 - 8:46

214

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Confusion about step in a proof that no group of order $120$ is simple

Published on 09 Apr 2026 - 9:08

404

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Which groups can be proven to be simple using Iwasawa criterion?

Published on 12 Apr 2026 - 20:25

287

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A group of order pq

Published on 10 May 2026 - 9:19

672

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Exercise about simple group of order 60

Published on 14 Apr 2026 - 7:43

644

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Is $G=HK$ if $G/H$ and $G/K$ are simple groups, where $H$ and $K$ are distinct normal subgroups of $G$?

Published on 12 Apr 2026 - 14:23

298

Views

If $G$ is finite simple and $H \le G$ has index $2m$, then an involution of $G$ is conjugate to one in $H$

Published on 16 Apr 2026 - 15:53

58

Views

Is there a simple group and a proper subgroup with a unique and equidistant intermediate?

Published on 14 Apr 2026 - 20:22

List Question

Show that $PSL(2,2)$ and $PSL(2,3)$ are not simple groups.

$\operatorname{Aut}(G)=S$ is non-abelian simple with $\operatorname{Out}(S)>1$.

Is every $2$-generated simple group $\frac{3}{2}$-generated?

Transitivity of $\Omega$ in subspace actions

There is no simple group of order 528

Elements in non-Abelian simple Groups.

Are free groups residually simple?

Suzuki and solvability of finite groups

Confusion about step in a proof that no group of order $120$ is simple

Which groups can be proven to be simple using Iwasawa criterion?

A group of order pq

Exercise about simple group of order 60

Is $G=HK$ if $G/H$ and $G/K$ are simple groups, where $H$ and $K$ are distinct normal subgroups of $G$?

If $G$ is finite simple and $H \le G$ has index $2m$, then an involution of $G$ is conjugate to one in $H$

Is there a simple group and a proper subgroup with a unique and equidistant intermediate?

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