List questions from solution-verification

Published on 10 Apr 2026 - 21:23

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Vanishing of cohomology of affine scheme

Published on 26 Mar 2026 - 8:08

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Prove: $R$ is local $\iff$ $R$ has exactly one maximal ideal.

Published on 25 Mar 2026 - 10:55

63

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Hamiltonian graph join

Published on 15 Apr 2026 - 16:50

49

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commenting on whether $f'(x)$ is even or odd.

Published on 16 Apr 2026 - 1:32

53

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Proving $(\mathbb{Z}/n\mathbb{Z},+)$ is a group

Published on 08 Apr 2026 - 21:00

73

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Proof gone wrong: why don't all domains have characteristic $0$?

Published on 15 Apr 2026 - 1:27

869

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Let $T:\textbf{R}^{n}\to\textbf{R}^{m}$ be a linear transformation. Show that there exists a number $M > 0$ such that $\|Tx\|\leq M\|x\|$.

Published on 16 Apr 2026 - 3:00

70

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Prove by contradiction that: $A∩B=B∩A$. Is my proof right?

Published on 16 Apr 2026 - 14:23

108

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Prove the following two statements about differentiability are equivalent

Published on 13 Apr 2026 - 0:33

114

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Find $g(x)$ if $f(x)= \begin{cases} -1, & -2 \leq x \leq 0 \\ x-1, & 0 < x \leq 2 \end{cases}$ and $g(x) = |f(x)| + f(|x|)$

Published on 17 Apr 2026 - 14:43

56

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Prove by contradiction that $A\cup B=B\cup A.$

Published on 15 Apr 2026 - 9:22

85

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If $f$ is differentiable at $x_{0}$, then $f$ is also differentiable in the direction $v$ at $x_{0}$, and $D_{v}f(x_{0}) = f'(x_{0})v$

Published on 17 Apr 2026 - 9:21

596

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Proving intersection of POsets is a POset - Reflexive

Published on 14 Apr 2026 - 5:29

666

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Application of Burnside's Lemma on the vertices of a cube

Published on 09 Apr 2026 - 11:22

List Question

How to prove that two series converge simultaneously?

Vanishing of cohomology of affine scheme

Prove: $R$ is local $\iff$ $R$ has exactly one maximal ideal.

Hamiltonian graph join

commenting on whether $f'(x)$ is even or odd.

Proving $(\mathbb{Z}/n\mathbb{Z},+)$ is a group

Proof gone wrong: why don't all domains have characteristic $0$?

Let $T:\textbf{R}^{n}\to\textbf{R}^{m}$ be a linear transformation. Show that there exists a number $M > 0$ such that $\|Tx\|\leq M\|x\|$.

Prove by contradiction that: $A∩B=B∩A$. Is my proof right?

Prove the following two statements about differentiability are equivalent

Find $g(x)$ if $f(x)= \begin{cases} -1, & -2 \leq x \leq 0 \\ x-1, & 0 < x \leq 2 \end{cases}$ and $g(x) = |f(x)| + f(|x|)$

Prove by contradiction that $A\cup B=B\cup A.$

If $f$ is differentiable at $x_{0}$, then $f$ is also differentiable in the direction $v$ at $x_{0}$, and $D_{v}f(x_{0}) = f'(x_{0})v$

Proving intersection of POsets is a POset - Reflexive

Application of Burnside's Lemma on the vertices of a cube

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