Question

Is it possible to find explict expressions for the eigenfunctions and eigenfrequencies of a Helmholtz transmission problem in one-dimension?

score 58 · Answer 1 · 2026-03-28 02:23:46

58

Views

Is it possible to find explict expressions for the eigenfunctions and eigenfrequencies of a Helmholtz transmission problem in one-dimension?

Published on 28 Mar 2026 - 2:23

score 179 · Answer 2 · 2026-03-30 17:02:48

179

Views

Show that the sum of spectrum is direct

Published on 30 Mar 2026 - 17:02

score 207 · Answer 3 · 2026-03-28 16:12:56

207

Views

Perturbation by bounded operators

Published on 28 Mar 2026 - 16:12

score 623 · Answer 4 · 2017-09-24 20:53:32

623

Views

Minimizing the Schatten 1-norm over symmetric matrices.

Published on 24 Sep 2017 - 20:53

score 109 · Answer 5 · 2017-09-28 05:33:27

109

Views

A sufficient condition for an unbounded self-adjoint operator to have point spectrum?

Published on 28 Sep 2017 - 5:33

score 119 · Answer 6 · 2017-09-30 07:20:48

119

Views

Is a unitary opertor with $\sigma(U)=\lbrace 1\rbrace$ necessarily be the identity?

Published on 30 Sep 2017 - 7:20

score 707 · Answer 7 · 2017-10-02 08:21:22

707

Views

Continuity of the functional calculus form of the Spectral Theorem

Published on 02 Oct 2017 - 8:21

score 100 · Answer 8 · 2026-03-31 01:47:39

100

Views

$\sigma(f)=f(\Omega)$ for $f\in C(\Omega)$, $\Omega$ a Compact, Hausdorff Topological Space

Published on 31 Mar 2026 - 1:47

score 28 · Answer 9 · 2026-03-29 22:29:54

28

Views

Riesz-Markov to define the Functional Caluculus, and the measure of the spectrum.

Published on 29 Mar 2026 - 22:29

score 215 · Answer 10 · 2026-02-24 03:48:00

215

Views

Spectral Decomposition: $A\psi = \lambda \psi \implies f(A)\psi = f(\lambda)\psi$

Published on 24 Feb 2026 - 3:48

score 47 · Answer 11 · 2017-10-09 13:31:58

47

Views

$f$ symmetric with positive eigenvalues $ \Longleftrightarrow\langle f(v),v\rangle>0~~v\neq0$

Published on 09 Oct 2017 - 13:31

score 592 · Answer 12 · 2017-10-09 23:49:53

592

Views

Definition of resolution of the identity

Published on 09 Oct 2017 - 23:49

score 305 · Answer 13 · 2026-02-24 03:48:14

305

Views

Spectral Theorem - $AB = BA \implies B\Phi(f) = \Phi(f)B$

Published on 24 Feb 2026 - 3:48

score 66 · Answer 14 · 2017-10-13 09:53:59

66

Views

$\int\frac{1}{\mu-\lambda}dP(\mu) (A-\lambda I)=I$ & Projection Valued Measures

Published on 13 Oct 2017 - 9:53

score 540 · Answer 15 · 2026-04-02 04:09:32

540

Views

How to see that group of unitary operators with strong operator topology is connected?

Published on 02 Apr 2026 - 4:09

List Question

Is it possible to find explict expressions for the eigenfunctions and eigenfrequencies of a Helmholtz transmission problem in one-dimension?

Show that the sum of spectrum is direct

Perturbation by bounded operators

Minimizing the Schatten 1-norm over symmetric matrices.

A sufficient condition for an unbounded self-adjoint operator to have point spectrum?

Is a unitary opertor with $\sigma(U)=\lbrace 1\rbrace$ necessarily be the identity?

Continuity of the functional calculus form of the Spectral Theorem

$\sigma(f)=f(\Omega)$ for $f\in C(\Omega)$, $\Omega$ a Compact, Hausdorff Topological Space

Riesz-Markov to define the Functional Caluculus, and the measure of the spectrum.

Spectral Decomposition: $A\psi = \lambda \psi \implies f(A)\psi = f(\lambda)\psi$

$f$ symmetric with positive eigenvalues $ \Longleftrightarrow\langle f(v),v\rangle>0~~v\neq0$

Definition of resolution of the identity

Spectral Theorem - $AB = BA \implies B\Phi(f) = \Phi(f)B$

$\int\frac{1}{\mu-\lambda}dP(\mu) (A-\lambda I)=I$ & Projection Valued Measures

How to see that group of unitary operators with strong operator topology is connected?

Trending Questions

Popular # Hahtags

Popular Questions