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15
Math.TechQA.Club
2016-09-15 19:47:50
443
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Closed formula for the sums $\sum\limits_{1 \le i_1 < i_2 < \dots < i_k \le n} i_1 i_2 \cdots i_k $?
Published on
15 Sep 2016 - 19:47
#combinatorics
#summation
#generating-functions
#closed-form
#stirling-numbers
280
Views
Stirling number of second kind S(m,4)
Published on
17 Sep 2016 - 0:41
#combinatorics
#discrete-mathematics
#stirling-numbers
#set-partition
309
Views
Any good approximations for Stirling numbers?
Published on
29 Sep 2016 - 12:16
#combinatorics
#combinations
#stirling-numbers
507
Views
Recurrence relation, unsigned stirling numbers of first kind
Published on
12 Oct 2016 - 13:11
#combinatorics
#recurrence-relations
#stirling-numbers
151
Views
Surjections using Stirling-numbers
Published on
18 Oct 2016 - 14:27
#combinatorics
#discrete-mathematics
#stirling-numbers
1.7k
Views
Proof of Dobinski's formula for Bell numbers
Published on
18 Oct 2016 - 20:08
#combinatorics
#stirling-numbers
921
Views
prove $\sum_{k=0}^n(-1)^k k!S_k^n = (-1)^n $
Published on
20 Oct 2016 - 13:18
#combinatorics
#discrete-mathematics
#combinations
#stirling-numbers
85
Views
Expression of the n-th derivative
Published on
26 Oct 2016 - 19:39
#combinatorics
#derivatives
#stirling-numbers
432
Views
Combinatorial interpretation of q-analog Stirling numbers of the second kind
Published on
25 Mar 2026 - 11:23
#combinatorics
#stirling-numbers
#q-analogs
396
Views
Evaluate sum involving stirling numbers of second kind using EGF
Published on
06 Nov 2016 - 17:41
#combinatorics
#generating-functions
#stirling-numbers
159
Views
Bell partial numbers
Published on
09 Nov 2016 - 21:17
#combinatorics
#reference-request
#stirling-numbers
#set-partition
81
Views
Exact Expression for the n-th Derivative
Published on
13 Nov 2016 - 3:39
#combinatorics
#derivatives
#stirling-numbers
140
Views
Striling number of second kind when each partition has at least $r $ elements
Published on
13 Nov 2016 - 20:12
#combinatorics
#recurrence-relations
#stirling-numbers
126
Views
Solution of this recurrence relation
Published on
14 Nov 2016 - 3:29
#combinatorics
#graph-theory
#recurrence-relations
#trees
#stirling-numbers
1.1k
Views
Stirling Numbers: Proof $S(n+1,m) = \sum_{k=0}^{n} {n \choose k}S(k,m-1)$
Published on
15 Nov 2016 - 18:43
#combinatorics
#recurrence-relations
#stirling-numbers
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