Question

Close form of a power series starting at $n=2$

score 172 · Answer 1 · 2026-04-10 22:02:42

172

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Close form of a power series starting at $n=2$

Published on 10 Apr 2026 - 22:02

score 172 · Answer 2 · 2026-04-08 20:59:34

172

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Easy Math question : Sum of squares

Published on 08 Apr 2026 - 20:59

score 78 · Answer 3 · 2014-03-18 18:43:55

78

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Sum of $k^4$ from $0$ to $n$

Published on 18 Mar 2014 - 18:43

score 649 · Answer 4 · 2014-03-18 19:50:34

649

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closed form for $\binom{n}{0}+\binom{n}{3}+\binom{n}{6}+...+\binom{n}{n}$

Published on 18 Mar 2014 - 19:50

score 1.3k · Answer 5 · 2026-04-02 21:54:07

1.3k

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Identity involving binomial coefficients: $\sum_{j=0}^i (-1)^{i+j}\binom {n-j}{i-j}\binom mj=\sum_{j=0}^i (-1)^{i+j}\binom {n-j+k}{i-j}\binom {m+k}j$

Published on 02 Apr 2026 - 21:54

score 36 · Answer 6 · 2026-04-10 17:03:03

36

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What steps and properties are involved in this Summation simplification?

Published on 10 Apr 2026 - 17:03

score 3k · Answer 7 · 2026-04-10 02:27:41

3k

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Lagrange polynomials sum to one

Published on 10 Apr 2026 - 2:27

score 130 · Answer 8 · 2026-04-09 15:22:40

130

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Expected value of a sum starting at a value given through a random variable

Published on 09 Apr 2026 - 15:22

score 75 · Answer 9 · 2014-03-19 14:32:12

75

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Find required increase per day. Find X

Published on 19 Mar 2014 - 14:32

score 47 · Answer 10 · 2014-03-19 16:37:28

47

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What is the infinite sum of regular numbers?

Published on 19 Mar 2014 - 16:37

score 420 · Answer 11 · 2026-04-02 21:50:26

420

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Another combinatorics problem: $\sum\limits_{k = 0}^n (-1)^k \binom{2n-k}k2^{2n-2k}=2n+1$

Published on 02 Apr 2026 - 21:50

score 636 · Answer 12 · 2026-04-02 14:49:36

636

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Help with proof using induction: $1 + \frac{1}{4} + \frac{1}{9}+\cdots+\frac{1}{n^2}\leq 2-\frac{1}{n}$

Published on 02 Apr 2026 - 14:49

score 555 · Answer 13 · 2026-03-26 11:01:42

555

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Using $S_n = \sum_{k=1}^{n}H_k$ where $H_k$ are the harmonic numbers, show $S_n = (n+1)H_n - n$

Published on 26 Mar 2026 - 11:01

score 11.5k · Answer 14 · 2014-03-19 21:47:27

11.5k

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What is the sum of $1^4 + 2^4 + 3^4+ \dots + n^4$ and the derivation for that expression

Published on 19 Mar 2014 - 21:47

score 2.4k · Answer 15 · 2026-03-29 14:57:54

2.4k

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Using the Parseval Identity to compute $ \sum_{n=1}^{+ \infty} \frac{1}{(4n^2-1)^2}$

Published on 29 Mar 2026 - 14:57

List Question

Close form of a power series starting at $n=2$

Easy Math question : Sum of squares

Sum of $k^4$ from $0$ to $n$

closed form for $\binom{n}{0}+\binom{n}{3}+\binom{n}{6}+...+\binom{n}{n}$

Identity involving binomial coefficients: $\sum_{j=0}^i (-1)^{i+j}\binom {n-j}{i-j}\binom mj=\sum_{j=0}^i (-1)^{i+j}\binom {n-j+k}{i-j}\binom {m+k}j$

What steps and properties are involved in this Summation simplification?

Lagrange polynomials sum to one

Expected value of a sum starting at a value given through a random variable

Find required increase per day. Find X

What is the infinite sum of regular numbers?

Another combinatorics problem: $\sum\limits_{k = 0}^n (-1)^k \binom{2n-k}k2^{2n-2k}=2n+1$

Help with proof using induction: $1 + \frac{1}{4} + \frac{1}{9}+\cdots+\frac{1}{n^2}\leq 2-\frac{1}{n}$

Using $S_n = \sum_{k=1}^{n}H_k$ where $H_k$ are the harmonic numbers, show $S_n = (n+1)H_n - n$

What is the sum of $1^4 + 2^4 + 3^4+ \dots + n^4$ and the derivation for that expression

Using the Parseval Identity to compute $ \sum_{n=1}^{+ \infty} \frac{1}{(4n^2-1)^2}$

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