Question

Understanding proof that supremum of lower bounds is infimum

score 399 · Answer 1 · 2020-04-05 14:04:10

399

Views

Understanding proof that supremum of lower bounds is infimum

Published on 05 Apr 2020 - 14:04

score 44 · Answer 2 · 2020-04-08 10:45:07

44

Views

Prove bounded sequences of real numbers

Published on 08 Apr 2020 - 10:45

score 90 · Answer 3 · 2020-04-09 13:01:52

90

Views

When does principle of iterated supremum fail?

Published on 09 Apr 2020 - 13:01

score 300 · Answer 4 · 2020-04-09 22:07:01

300

Views

Mean Value Theorem Stated as an Inequality

Published on 09 Apr 2020 - 22:07

score 54 · Answer 5 · 2020-04-11 18:30:37

54

Views

Implication of infimum

Published on 11 Apr 2020 - 18:30

score 169 · Answer 6 · 2026-03-27 10:12:02

169

Views

Are the stopping times $\tau_1 = \inf\{t \geq 0: X_t > a\}$ and $\tau_2 = \inf\{t \geq 0: X_t = a\}$ equivalent?

Published on 27 Mar 2026 - 10:12

score 702 · Answer 7 · 2020-04-14 15:25:24

702

Views

Determine infimum/supremum of the set $\{\frac{n-m}{n+m} \vert n,m \in \mathbb{N}_0\}$

Published on 14 Apr 2020 - 15:25

score 15 · Answer 8 · 2020-04-14 19:05:04

15

Views

confirmation of an equality regarding norm of a vector-valued function

Published on 14 Apr 2020 - 19:05

score 65 · Answer 9 · 2020-04-15 08:26:33

65

Views

Prove that the given statements are true/false

Published on 15 Apr 2020 - 8:26

score 147 · Answer 10 · 2020-04-15 19:01:15

147

Views

How to prove there exists a subsequence $(x_{n_k})$ of $(x_n)$ such that $\lim(x_{n_k})=y$?

Published on 15 Apr 2020 - 19:01

score 115 · Answer 11 · 2020-04-15 23:30:21

115

Views

Proof verification: Let $a_{n}$ be a sequence of real numbers bounded by $M\in\textbf{R}$, and which is also increasing. Then $a_{n}$ is convergent.

Published on 15 Apr 2020 - 23:30

score 465 · Answer 12 · 2020-04-17 03:32:38

465

Views

Let $f:[0,1]\to \mathbb{R}$ be a bounded function. Which of the following $may$ be true statement(s)?

Published on 17 Apr 2020 - 3:32

score 19 · Answer 13 · 2020-04-19 12:05:05

19

Views

Let $A=\{\frac{\lfloor nb\rfloor }{n}\},b>0$ prove that $supA=b$

Published on 19 Apr 2020 - 12:05

score 55 · Answer 14 · 2020-04-19 18:50:54

55

Views

Analysis proof involving bounded intervals

Published on 19 Apr 2020 - 18:50

score 135 · Answer 15 · 2020-04-21 06:52:42

135

Views

Proof that supremum doesn' exist

Published on 21 Apr 2020 - 6:52

List Question

Understanding proof that supremum of lower bounds is infimum

Prove bounded sequences of real numbers

When does principle of iterated supremum fail?

Mean Value Theorem Stated as an Inequality

Implication of infimum

Are the stopping times $\tau_1 = \inf\{t \geq 0: X_t > a\}$ and $\tau_2 = \inf\{t \geq 0: X_t = a\}$ equivalent?

Determine infimum/supremum of the set $\{\frac{n-m}{n+m} \vert n,m \in \mathbb{N}_0\}$

confirmation of an equality regarding norm of a vector-valued function

Prove that the given statements are true/false

How to prove there exists a subsequence $(x_{n_k})$ of $(x_n)$ such that $\lim(x_{n_k})=y$?

Proof verification: Let $a_{n}$ be a sequence of real numbers bounded by $M\in\textbf{R}$, and which is also increasing. Then $a_{n}$ is convergent.

Let $f:[0,1]\to \mathbb{R}$ be a bounded function. Which of the following $may$ be true statement(s)?

Let $A=\{\frac{\lfloor nb\rfloor }{n}\},b>0$ prove that $supA=b$

Analysis proof involving bounded intervals

Proof that supremum doesn' exist

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