Question

Equivalent condition for finite Nilpotent group

score 60 · Answer 1 · 2019-10-02 08:15:01

60

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Equivalent condition for finite Nilpotent group

Published on 02 Oct 2019 - 8:15

score 135 · Answer 2 · 2026-03-25 16:01:57

135

Views

There is no simple group of order $pq^2$.

Published on 25 Mar 2026 - 16:01

score 108 · Answer 3 · 2019-10-05 17:09:55

108

Views

The only conjugacy class of the conjugates of a $\textit{p}$-Sylow subgroup $K$ with a single element is $[K]$.

Published on 05 Oct 2019 - 17:09

score 114 · Answer 4 · 2019-10-05 17:23:34

114

Views

Normality of the maximal subgroups of the Sylow $p$-subgroups

Published on 05 Oct 2019 - 17:23

score 101 · Answer 5 · 2026-03-26 07:03:35

101

Views

Nilpotent Group G

Published on 26 Mar 2026 - 7:03

score 121 · Answer 6 · 2019-10-11 12:26:05

121

Views

Construction of groups with arbitrarily $n_p$ number of Sylow $p$-subgroups

Published on 11 Oct 2019 - 12:26

score 204 · Answer 7 · 2019-10-11 15:29:53

204

Views

Can a Sylow $p$-subgroup be conjugate to anything other than another Sylow $p$-subgroup?

Published on 11 Oct 2019 - 15:29

score 139 · Answer 8 · 2019-10-16 20:32:09

139

Views

Proving an Automorphism of the symmetric group $S_4$ is the identity.

Published on 16 Oct 2019 - 20:32

score 554 · Answer 9 · 2019-10-17 10:34:45

554

Views

How to show that a group of order $380$ always has a normal subgroup of $95$

Published on 17 Oct 2019 - 10:34

score 31 · Answer 10 · 2026-02-23 06:38:40

31

Views

Article: Invariant Sylow subgroups and solvability of finite groups - Antonio Beltran.

Published on 23 Feb 2026 - 6:38

score 146 · Answer 11 · 2019-10-23 08:28:23

146

Views

$G$ be a finite group, if $H\lneq G$ and $|G| \nmid [G:H]!$. Prove $G$ is not simple

Published on 23 Oct 2019 - 8:28

score 440 · Answer 12 · 2019-10-23 08:45:25

440

Views

Let G be a finite group, $|G| = 1575$ and suppose $n_3 =1$. Prove $G$ is abelian

Published on 23 Oct 2019 - 8:45

score 77 · Answer 13 · 2019-10-28 02:47:02

77

Views

Question on Artin Proof of The Classification of The Groups of Order $12$

Published on 28 Oct 2019 - 2:47

score 47 · Answer 14 · 2026-03-27 03:50:51

47

Views

Bound Index of Centralizer

Published on 27 Mar 2026 - 3:50

score 239 · Answer 15 · 2019-11-03 16:11:47

239

Views

If $G$ be a group of order $105$ and if a Sylow $3$- subgroup is normal in $G$, then $G$ is abelian.

Published on 03 Nov 2019 - 16:11

List Question

Equivalent condition for finite Nilpotent group

There is no simple group of order $pq^2$.

The only conjugacy class of the conjugates of a $\textit{p}$-Sylow subgroup $K$ with a single element is $[K]$.

Normality of the maximal subgroups of the Sylow $p$-subgroups

Nilpotent Group G

Construction of groups with arbitrarily $n_p$ number of Sylow $p$-subgroups

Can a Sylow $p$-subgroup be conjugate to anything other than another Sylow $p$-subgroup?

Proving an Automorphism of the symmetric group $S_4$ is the identity.

How to show that a group of order $380$ always has a normal subgroup of $95$

Article: Invariant Sylow subgroups and solvability of finite groups - Antonio Beltran.

$G$ be a finite group, if $H\lneq G$ and $|G| \nmid [G:H]!$. Prove $G$ is not simple

Let G be a finite group, $|G| = 1575$ and suppose $n_3 =1$. Prove $G$ is abelian

Question on Artin Proof of The Classification of The Groups of Order $12$

Bound Index of Centralizer

If $G$ be a group of order $105$ and if a Sylow $3$- subgroup is normal in $G$, then $G$ is abelian.

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