Question

Group of order $|G|=6545$ has either a normal Sylow 5-subgroup or a normal Sylow 17-subgroup.

score 1.9k · Answer 1 · 2018-05-09 22:37:05

1.9k

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Group of order $|G|=6545$ has either a normal Sylow 5-subgroup or a normal Sylow 17-subgroup.

Published on 09 May 2018 - 22:37

score 125 · Answer 2 · 2018-05-15 01:39:37

125

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Sylow subgroups/subgroup lattices in algebraic topology?

Published on 15 May 2018 - 1:39

score 62 · Answer 3 · 2026-03-25 01:15:18

62

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On the non-nilpotent solvable groups

Published on 25 Mar 2026 - 1:15

score 1.9k · Answer 4 · 2018-05-23 13:12:28

1.9k

Views

A group of order 20

Published on 23 May 2018 - 13:12

score 212 · Answer 5 · 2018-05-27 08:07:56

212

Views

Show that $GL_2(\mathbb{F}_p)$ has only one conjugacy class of order $p$.

Published on 27 May 2018 - 8:07

score 169 · Answer 6 · 2018-05-31 13:33:00

169

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Finite simple group $G$ containing no elements of order $5$

Published on 31 May 2018 - 13:33

score 94 · Answer 7 · 2018-06-09 16:27:42

94

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Question about proof of classifying groups of order $pq$

Published on 09 Jun 2018 - 16:27

score 74 · Answer 8 · 2018-06-13 10:36:38

74

Views

On the subgroups properties of $A_5$

Published on 13 Jun 2018 - 10:36

score 1.5k · Answer 9 · 2026-03-25 00:07:40

1.5k

Views

How to prove that a finite group of order $280$ is not simple?

Published on 25 Mar 2026 - 0:07

score 503 · Answer 10 · 2018-06-21 22:52:33

503

Views

How to prove: if $G$ finite, $P$ a subgroup or order $p$ and $P = C_G(P)$ then $P$ is a Sylow $p$-subgroup of $G$

Published on 21 Jun 2018 - 22:52

score 723 · Answer 11 · 2018-06-23 12:27:47

723

Views

Find the $5$-sylow subgroup of the symmetric group $S_{24}$

Published on 23 Jun 2018 - 12:27

score 1.3k · Answer 12 · 2026-03-25 00:07:54

1.3k

Views

Show that every group of order $5865$ is cyclic

Published on 25 Mar 2026 - 0:07

score 880 · Answer 13 · 2026-03-25 00:07:50

880

Views

Prove that there is no simple group of order $144$

Published on 25 Mar 2026 - 0:07

score 535 · Answer 14 · 2018-07-01 20:02:59

535

Views

Prove that any group of order 392 has a normal group of order 7 or 49

Published on 01 Jul 2018 - 20:02

score 220 · Answer 15 · 2018-07-02 02:52:31

220

Views

Let$G$ be a group of order $12$ with $4$ Sylow $3$-subgroups, affording permutation representation $\phi : G \to S_4$. Prove that $ker \phi = 1$.

Published on 02 Jul 2018 - 2:52

List Question

Group of order $|G|=6545$ has either a normal Sylow 5-subgroup or a normal Sylow 17-subgroup.

Sylow subgroups/subgroup lattices in algebraic topology?

On the non-nilpotent solvable groups

A group of order 20

Show that $GL_2(\mathbb{F}_p)$ has only one conjugacy class of order $p$.

Finite simple group $G$ containing no elements of order $5$

Question about proof of classifying groups of order $pq$

On the subgroups properties of $A_5$

How to prove that a finite group of order $280$ is not simple?

How to prove: if $G$ finite, $P$ a subgroup or order $p$ and $P = C_G(P)$ then $P$ is a Sylow $p$-subgroup of $G$

Find the $5$-sylow subgroup of the symmetric group $S_{24}$

Show that every group of order $5865$ is cyclic

Prove that there is no simple group of order $144$

Prove that any group of order 392 has a normal group of order 7 or 49

Let$G$ be a group of order $12$ with $4$ Sylow $3$-subgroups, affording permutation representation $\phi : G \to S_4$. Prove that $ker \phi = 1$.

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