Question

Find the Taylor-series expansion of a square of a rational function of a complex variable

score 923 · Answer 1 · 2026-04-10 21:45:32

923

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Find the Taylor-series expansion of a square of a rational function of a complex variable

Published on 10 Apr 2026 - 21:45

score 94 · Answer 2 · 2016-07-12 14:55:23

94

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Difference/switch between big/small o in taylor series

Published on 12 Jul 2016 - 14:55

score 81 · Answer 3 · 2016-07-13 10:02:19

81

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Convergence of the series $\sum \frac{(-1)^{n}}{n^{\frac{2}{3}}+n^{\frac{1}{3}}+(-1)^{n}}$

Published on 13 Jul 2016 - 10:02

score 121 · Answer 4 · 2016-07-13 15:33:44

121

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Show that $\frac{(-1)^n}{n+(-1)^n\sqrt{n+1}}=\frac{(-1)^n}n+\mathcal{O}\left(\frac{1}{n^{3/2}}\right)$

Published on 13 Jul 2016 - 15:33

score 240 · Answer 5 · 2026-04-01 18:31:47

240

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Taylor expansion of Crystal Field potentials

Published on 01 Apr 2026 - 18:31

score 1.2k · Answer 6 · 2026-04-11 03:20:32

1.2k

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Taylor polynomial in function composition

Published on 11 Apr 2026 - 3:20

score 104 · Answer 7 · 2016-07-14 10:55:45

104

Views

Show that $(-1)^{n}\left(\sqrt{n+1}-\sqrt{n} \right)=\tfrac{(-1)^{n}}{2\sqrt{n}}+\mathcal{O}\left(\tfrac{1}{n^{3/2}} \right)$

Published on 14 Jul 2016 - 10:55

score 69 · Answer 8 · 2016-07-14 19:01:08

69

Views

Show that $(-1)^{n}\sqrt[n]{n}\sin(\frac{1}{n})=\tfrac{(-1)^{n}}{n}+\mathcal{O}\left(\tfrac{\ln(n)}{n^{2}} \right)$

Published on 14 Jul 2016 - 19:01

score 78 · Answer 9 · 2016-07-14 22:30:14

78

Views

Taylor expansion $f(x)=f(0)$

Published on 14 Jul 2016 - 22:30

score 234 · Answer 10 · 2026-04-11 17:30:40

234

Views

How would Taylor Series work?

Published on 11 Apr 2026 - 17:30

score 23 · Answer 11 · 2016-07-15 12:39:07

Show that $\tfrac{(-1)^{n}}{\cos(n)+n^{\tfrac{3}{4}}}=\tfrac{(-1)^{n}}{n^{\tfrac{3}{4}}}+\mathcal{O}\left( \tfrac{1}{n^{\tfrac{3}{2}}}\right) $

score 72 · Answer 12 · 2016-07-15 14:35:41

Show : $(-1)^{n}n^{-\tan\left(\tfrac{\pi}{4}+\tfrac{1}{n} \right)}=\tfrac{(-1)^{n}}{n}+\mathcal{O}\left(\tfrac{\ln(n)}{n^{2}} \right)$

score 2.1k · Answer 13 · 2016-07-16 00:38:11

2.1k

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Find the general formula for this Macluaurin series

Published on 16 Jul 2016 - 0:38

score 283 · Answer 14 · 2016-07-16 01:38:38

283

Views

Is there any approximation expression of finite sum of exponential taylor series

Published on 16 Jul 2016 - 1:38

score 194 · Answer 15 · 2016-07-16 02:31:30

194

Views

Find the general formula for this Taylor series

Published on 16 Jul 2016 - 2:31

List Question

Find the Taylor-series expansion of a square of a rational function of a complex variable

Difference/switch between big/small o in taylor series

Convergence of the series $\sum \frac{(-1)^{n}}{n^{\frac{2}{3}}+n^{\frac{1}{3}}+(-1)^{n}}$

Show that $\frac{(-1)^n}{n+(-1)^n\sqrt{n+1}}=\frac{(-1)^n}n+\mathcal{O}\left(\frac{1}{n^{3/2}}\right)$

Taylor expansion of Crystal Field potentials

Taylor polynomial in function composition

Show that $(-1)^{n}\left(\sqrt{n+1}-\sqrt{n} \right)=\tfrac{(-1)^{n}}{2\sqrt{n}}+\mathcal{O}\left(\tfrac{1}{n^{3/2}} \right)$

Show that $(-1)^{n}\sqrt[n]{n}\sin(\frac{1}{n})=\tfrac{(-1)^{n}}{n}+\mathcal{O}\left(\tfrac{\ln(n)}{n^{2}} \right)$

Taylor expansion $f(x)=f(0)$

How would Taylor Series work?

Show that $\tfrac{(-1)^{n}}{\cos(n)+n^{\tfrac{3}{4}}}=\tfrac{(-1)^{n}}{n^{\tfrac{3}{4}}}+\mathcal{O}\left( \tfrac{1}{n^{\tfrac{3}{2}}}\right) $

Show : $(-1)^{n}n^{-\tan\left(\tfrac{\pi}{4}+\tfrac{1}{n} \right)}=\tfrac{(-1)^{n}}{n}+\mathcal{O}\left(\tfrac{\ln(n)}{n^{2}} \right)$

Find the general formula for this Macluaurin series

Is there any approximation expression of finite sum of exponential taylor series

Find the general formula for this Taylor series

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