Question

How do I take high order derivatives for a Taylor expansion?

score 213 · Answer 1 · 2026-04-09 06:06:54

213

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How do I take high order derivatives for a Taylor expansion?

Published on 09 Apr 2026 - 6:06

score 90 · Answer 2 · 2016-08-25 20:36:43

90

Views

Find the Taylor series of function $\frac{-x^2-x-1}{x^3 - 2x^2 + 3x -6}$

Published on 25 Aug 2016 - 20:36

score 1.3k · Answer 3 · 2026-04-11 00:59:52

1.3k

Views

Deriving Relative Risk premium by a Taylor series

Published on 11 Apr 2026 - 0:59

score 161 · Answer 4 · 2016-08-26 17:25:30

161

Views

Can the limit $\lim_{x\to0}\left(\frac{1}{x^5}\int_0^xe^{-t^2}\,dt-\frac{1}{x^4}+\frac{1}{3x^2}\right)$ be calculated?

Published on 26 Aug 2016 - 17:25

score 417 · Answer 5 · 2026-03-28 20:57:56

417

Views

Examples of limits that become easier with Taylor series

Published on 28 Mar 2026 - 20:57

score 225 · Answer 6 · 2026-04-11 18:59:54

225

Views

Applying MVT and IVT (?) to show something about f'''? (edit: actually, Taylor's Theorem using Lagrange remainder)

Published on 11 Apr 2026 - 18:59

score 50 · Answer 7 · 2026-04-10 17:12:11

50

Views

Taylor Expansion involving $e^y$

Published on 10 Apr 2026 - 17:12

score 214 · Answer 8 · 2026-03-25 22:09:53

214

Views

Analytic Continuation for the case : $\sum_{1}^{\infty} 1$

Published on 25 Mar 2026 - 22:09

score 87 · Answer 9 · 2016-08-28 17:25:29

87

Views

Find any rational approximation of $a = \frac{\sin(\sqrt{2})}{\sqrt{2}}$

Published on 28 Aug 2016 - 17:25

score 165 · Answer 10 · 2016-08-29 20:37:41

165

Views

Taylor Series, Taylor Theorem

Published on 29 Aug 2016 - 20:37

score 2k · Answer 11 · 2016-08-30 21:52:13

2k

Views

Lagrange error for approximating $\frac{1}{x^2}$ with a second-degree Taylor polynomial about $x = 1$

Published on 30 Aug 2016 - 21:52

score 199 · Answer 12 · 2026-03-29 05:58:41

199

Views

Expansion in series acoording to descending powers of $\frac{1}{\sqrt{(x+R)^2+y^2+z^2}}$

Published on 29 Mar 2026 - 5:58

score 246 · Answer 13 · 2026-04-09 14:48:16

246

Views

How to compute the first three terms of the Taylor expansion?

Published on 09 Apr 2026 - 14:48

score 167 · Answer 14 · 2016-08-31 10:48:23

167

Views

Prove that $a^3+b^3+c^3=1+3abc$, where $a$, $b$ and $c$ are power series.

Published on 31 Aug 2016 - 10:48

score 139 · Answer 15 · 2016-09-01 03:08:18

139

Views

Taylor/Maclaurin series type question

Published on 01 Sep 2016 - 3:08

List Question

How do I take high order derivatives for a Taylor expansion?

Find the Taylor series of function $\frac{-x^2-x-1}{x^3 - 2x^2 + 3x -6}$

Deriving Relative Risk premium by a Taylor series

Can the limit $\lim_{x\to0}\left(\frac{1}{x^5}\int_0^xe^{-t^2}\,dt-\frac{1}{x^4}+\frac{1}{3x^2}\right)$ be calculated?

Examples of limits that become easier with Taylor series

Applying MVT and IVT (?) to show something about f'''? (edit: actually, Taylor's Theorem using Lagrange remainder)

Taylor Expansion involving $e^y$

Analytic Continuation for the case : $\sum_{1}^{\infty} 1$

Find any rational approximation of $a = \frac{\sin(\sqrt{2})}{\sqrt{2}}$

Taylor Series, Taylor Theorem

Lagrange error for approximating $\frac{1}{x^2}$ with a second-degree Taylor polynomial about $x = 1$

Expansion in series acoording to descending powers of $\frac{1}{\sqrt{(x+R)^2+y^2+z^2}}$

How to compute the first three terms of the Taylor expansion?

Prove that $a^3+b^3+c^3=1+3abc$, where $a$, $b$ and $c$ are power series.

Taylor/Maclaurin series type question

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