Question

Sum the series : $\frac{1}{9\sqrt11 + 11\sqrt9} +\frac{1}{11\sqrt13 + 13\sqrt11} +\ldots$

score 225 · Answer 1 · 2020-11-11 15:10:56

225

Views

Sum the series : $\frac{1}{9\sqrt11 + 11\sqrt9} +\frac{1}{11\sqrt13 + 13\sqrt11} +\ldots$

Published on 11 Nov 2020 - 15:10

score 195 · Answer 2 · 2020-11-20 11:50:33

195

Views

Non-linear recurrence relation $\frac{a_n - a_{n+1}}{1 + a_na_{n+1}} = \frac{1}{2n^2}$

Published on 20 Nov 2020 - 11:50

score 210 · Answer 3 · 2020-11-20 16:12:23

210

Views

How to find sum of $\frac{1}{2}+\frac{3}{8}+\frac{15}{48}+\frac{105}{384}+\cdots$?

Published on 20 Nov 2020 - 16:12

score 432 · Answer 4 · 2020-12-14 21:48:30

432

Views

Alternating, Telescoping series convergence

Published on 14 Dec 2020 - 21:48

score 102 · Answer 5 · 2021-01-01 19:18:27

102

Views

Evaluate:$\sum_{n=2}^{\infty}\frac{\tan \theta_{n}}{3^n\left(3-\tan^2\theta_{n}\right)}$

Published on 01 Jan 2021 - 19:18

score 90 · Answer 6 · 2021-01-02 11:46:23

90

Views

Why is $\sum_{k=2}^{\infty} \frac{k}{k^{2}-1}=\sum_{k=2}^{\infty}\left(\frac{1}{k-1}+\frac{1}{k+1}\right)$?

Published on 02 Jan 2021 - 11:46

score 339 · Answer 7 · 2021-01-10 18:36:27

339

Views

Evaluating $\sum_{r=1}^{\infty} \cot^{-1}(ar^2+br+c)$

Published on 10 Jan 2021 - 18:36

score 168 · Answer 8 · 2021-01-25 10:46:02

168

Views

Telescoping series: $\sum\limits_{n=1}^{∞}[\tan^{-1}(2n+1)-\tan^{-1}(2n-1)]$

Published on 25 Jan 2021 - 10:46

score 76 · Answer 9 · 2021-01-26 10:00:41

76

Views

I have to show that the sum of this double series is $\frac{1}{2}$

Published on 26 Jan 2021 - 10:00

score 158 · Answer 10 · 2021-02-14 14:39:07

158

Views

How to compute $1 \times 2 \times 3 \times 4 + 3 \times 4 \times 5 \times 6 + ... + 97 \times 98 \times 99 \times 100$

Published on 14 Feb 2021 - 14:39

score 237 · Answer 11 · 2021-02-22 02:44:35

237

Views

How to use telescoping series to find: $\sum_{r=1}^{n}\frac{1}{r+2}$

Published on 22 Feb 2021 - 2:44

score 52 · Answer 12 · 2021-02-24 13:59:36

52

Views

Why does this telescoping series end up with a 2 in the numerator?

Published on 24 Feb 2021 - 13:59

score 205 · Answer 13 · 2021-02-25 20:49:41

205

Views

How would I evaluate this series using telescopic summation?

Published on 25 Feb 2021 - 20:49

score 69 · Answer 14 · 2021-02-26 01:33:20

69

Views

Is how I evaluated the following product correct $\prod_{n=1}^{20}(1+\frac{2n+1}{n^2})$?

Published on 26 Feb 2021 - 1:33

score 460 · Answer 15 · 2021-03-10 15:40:35

460

Views

Finding a formula for the kth partial sum

Published on 10 Mar 2021 - 15:40

List Question

Sum the series : $\frac{1}{9\sqrt11 + 11\sqrt9} +\frac{1}{11\sqrt13 + 13\sqrt11} +\ldots$

Non-linear recurrence relation $\frac{a_n - a_{n+1}}{1 + a_na_{n+1}} = \frac{1}{2n^2}$

How to find sum of $\frac{1}{2}+\frac{3}{8}+\frac{15}{48}+\frac{105}{384}+\cdots$?

Alternating, Telescoping series convergence

Evaluate:$\sum_{n=2}^{\infty}\frac{\tan \theta_{n}}{3^n\left(3-\tan^2\theta_{n}\right)}$

Why is $\sum_{k=2}^{\infty} \frac{k}{k^{2}-1}=\sum_{k=2}^{\infty}\left(\frac{1}{k-1}+\frac{1}{k+1}\right)$?

Evaluating $\sum_{r=1}^{\infty} \cot^{-1}(ar^2+br+c)$

Telescoping series: $\sum\limits_{n=1}^{∞}[\tan^{-1}(2n+1)-\tan^{-1}(2n-1)]$

I have to show that the sum of this double series is $\frac{1}{2}$

How to compute $1 \times 2 \times 3 \times 4 + 3 \times 4 \times 5 \times 6 + ... + 97 \times 98 \times 99 \times 100$

How to use telescoping series to find: $\sum_{r=1}^{n}\frac{1}{r+2}$

Why does this telescoping series end up with a 2 in the numerator?

How would I evaluate this series using telescopic summation?

Is how I evaluated the following product correct $\prod_{n=1}^{20}(1+\frac{2n+1}{n^2})$?

Finding a formula for the kth partial sum

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