Question

In general, what is the rank of a differential form?

score 771 · Answer 1 · 2015-04-24 23:55:42

771

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In general, what is the rank of a differential form?

Published on 24 Apr 2015 - 23:55

score 276 · Answer 2 · 2015-04-26 19:26:55

276

Views

Maps that preserve tensor rank

Published on 26 Apr 2015 - 19:26

score 65 · Answer 3 · 2015-04-28 23:43:28

65

Views

Can the following simple tensor preserving map exist?

Published on 28 Apr 2015 - 23:43

score 67 · Answer 4 · 2015-06-22 03:38:05

if $\mathrm{rank}(A)=m$ and $\mathrm{rank}(B)=n$, is that true that $\mathrm{rank}(A\otimes B)$ equal to $\mathrm{rank}(A)*\mathrm{rank}(B)$?

score 4.3k · Answer 5 · 2015-07-13 08:18:46

4.3k

Views

How to compute tensor product between two functions

Published on 13 Jul 2015 - 8:18

score 241 · Answer 6 · 2015-08-05 10:30:09

241

Views

$d \times d \times d$ tensor rank vs $d \times d$ tensor rank

Published on 05 Aug 2015 - 10:30

score 350 · Answer 7 · 2015-08-28 17:15:22

350

Views

Border rank of tensors

Published on 28 Aug 2015 - 17:15

score 51 · Answer 8 · 2015-10-24 01:47:55

51

Views

Is there any clue for the supremum of projective norm in an unit ball of injective tensor product space

Published on 24 Oct 2015 - 1:47

score 1.4k · Answer 9 · 2016-01-10 12:17:05

1.4k

Views

How many components of an antisymmetric rank five tensor on $ \mathbb{R}^5 $ are independent?

Published on 10 Jan 2016 - 12:17

score 475 · Answer 10 · 2016-02-28 20:10:51

475

Views

Can we get a tensor out of summation of one vector with its transpose?

Published on 28 Feb 2016 - 20:10

score 227 · Answer 11 · 2016-04-06 03:46:36

227

Views

Why the trace norm of a tensor is a good approximation to its rank?

Published on 06 Apr 2016 - 3:46

score 83 · Answer 12 · 2016-04-10 04:37:01

83

Views

Is $\max_{\|x\|_p=\|y\|_p=1} |\langle x, Ay\rangle|$ equivalent to $\max_{\|x\|_p=|} |\langle x, Ax\rangle|$ for symmetric $A$ & $p\geq 2$?

Published on 10 Apr 2016 - 4:37

score 118 · Answer 13 · 2016-05-14 13:06:27

118

Views

Why is lowering and raising index not affecting the value of a tensor?

Published on 14 May 2016 - 13:06

score 354 · Answer 14 · 2016-06-19 18:26:38

354

Views

Since the variance matrix is the expected value of a dyadic tensor, why is it not singular? Which is the probabilistic property behind that?

Published on 19 Jun 2016 - 18:26

score 95 · Answer 15 · 2013-05-08 14:24:59

95

Views

Is a $1^{\mathrm{st}}$ rank tensor identical to a vector?

Published on 08 May 2013 - 14:24

List Question

In general, what is the rank of a differential form?

Maps that preserve tensor rank

Can the following simple tensor preserving map exist?

if $\mathrm{rank}(A)=m$ and $\mathrm{rank}(B)=n$, is that true that $\mathrm{rank}(A\otimes B)$ equal to $\mathrm{rank}(A)*\mathrm{rank}(B)$?

How to compute tensor product between two functions

$d \times d \times d$ tensor rank vs $d \times d$ tensor rank

Border rank of tensors

Is there any clue for the supremum of projective norm in an unit ball of injective tensor product space

How many components of an antisymmetric rank five tensor on $ \mathbb{R}^5 $ are independent?

Can we get a tensor out of summation of one vector with its transpose?

Why the trace norm of a tensor is a good approximation to its rank?

Is $\max_{\|x\|_p=\|y\|_p=1} |\langle x, Ay\rangle|$ equivalent to $\max_{\|x\|_p=|} |\langle x, Ax\rangle|$ for symmetric $A$ & $p\geq 2$?

Why is lowering and raising index not affecting the value of a tensor?

Since the variance matrix is the expected value of a dyadic tensor, why is it not singular? Which is the probabilistic property behind that?

Is a $1^{\mathrm{st}}$ rank tensor identical to a vector?

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