Question

If $x, y \in [0,10]$ then what is the number of solutions $(x, y)$ of the inequation $3^{sec^2x - 1} \sqrt{9y^2-6y+2} \le 1$

score 430 · Answer 1 · 2026-03-25 01:29:05

430

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If $x, y \in [0,10]$ then what is the number of solutions $(x, y)$ of the inequation $3^{sec^2x - 1} \sqrt{9y^2-6y+2} \le 1$

Published on 25 Mar 2026 - 1:29

score 55 · Answer 2 · 2026-03-20 03:39:15

55

Views

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score 62 · Answer 3 · 2018-01-21 20:40:00

62

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score 211 · Answer 4 · 2018-01-21 22:13:19

211

Views

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score 134 · Answer 5 · 2018-01-21 23:02:01

134

Views

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score 493 · Answer 6 · 2026-03-24 22:08:15

493

Views

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score 82 · Answer 7 · 2018-01-22 01:02:21

82

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111

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90

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score 41 · Answer 12 · 2018-01-22 18:25:35

41

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score 2.5k · Answer 13 · 2018-01-22 21:42:33

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score 92 · Answer 14 · 2018-01-22 22:06:16

92

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Published on 22 Jan 2018 - 22:06

score 83 · Answer 15 · 2026-03-30 16:01:36

83

Views

Derive the conditions for $\tan^{-1}\frac{a\cos x-b\sin x}{b\cos x+a\sin x}=\tan^{-1}\frac{a}{b}-x$

Published on 30 Mar 2026 - 16:01

List Question

If $x, y \in [0,10]$ then what is the number of solutions $(x, y)$ of the inequation $3^{sec^2x - 1} \sqrt{9y^2-6y+2} \le 1$

Trigonometry: Negative cosine to polar form

Integral of sin(x) problem.

Arcsin(1) has many solutions. Which one to use when evaluating definite integral of derivative of arcsin, arccos, etc.?

Why does $\lim_{x \rightarrow \infty} {\frac{1+\cos(x)}{1}}$ have no limit?

Why I can't use acute trigonometric function in obtuse angles?

Find all $x$ in the interval without a graphing calculator

How using law of cosines determines angle between two vectors

sign function and absolute value of sin

Relating the roots of quadratic to an inverse trigonometric functions' question

Recurrent definition of sine function

How to find the exact angle by hand from given trigonometric function value?

Finding the height of the flagpole

Showing $1/\left(\frac{1}{\cos(x)} + \frac{\sin(x)}{\cos(x)}\right)$

Derive the conditions for $\tan^{-1}\frac{a\cos x-b\sin x}{b\cos x+a\sin x}=\tan^{-1}\frac{a}{b}-x$

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