Question

composition of a continuous function with another function which is not uniformly continuous

score 16 · Answer 1 · 2022-06-09 18:02:32

16

Views

composition of a continuous function with another function which is not uniformly continuous

Published on 09 Jun 2022 - 18:02

score 60 · Answer 2 · 2022-06-16 08:28:58

60

Views

Why are continuous functions, especially uniformly continuous function so important in generalization (estimating future values)?

Published on 16 Jun 2022 - 8:28

score 16 · Answer 3 · 2022-06-16 17:18:48

16

Views

uniformly continuity and boundedness of periodic function

Published on 16 Jun 2022 - 17:18

score 30 · Answer 4 · 2022-06-19 20:15:28

30

Views

Understanding uniform continuity - why is an upper estimate here allowed?

Published on 19 Jun 2022 - 20:15

score 51 · Answer 5 · 2026-03-30 12:25:59

51

Views

(Uniform) continuity in the proof of Müntz theorem

Published on 30 Mar 2026 - 12:25

score 147 · Answer 6 · 2022-06-23 10:15:02

147

Views

If $f$ is uniformly continuous on every finite subinterval of $[a,\infty)$, then is it necessary that $f$ is uniformly continuous on $[a,\infty)$?

Published on 23 Jun 2022 - 10:15

score 53 · Answer 7 · 2022-06-23 10:57:28

53

Views

If $f:[a,\infty) \to \mathbb R$ is uniformly continuous and $\lim_{x \to \infty}f(x)$ is finite, then show that $f$ is bounded on $[a,\infty)$

Published on 23 Jun 2022 - 10:57

score 68 · Answer 8 · 2022-06-23 11:14:34

68

Views

Can I find a modulus of continuity in this case?

Published on 23 Jun 2022 - 11:14

score 105 · Answer 9 · 2022-06-25 22:30:05

105

Views

The intuitive meaning of uniform continuity

Published on 25 Jun 2022 - 22:30

score 20 · Answer 10 · 2026-04-02 23:22:08

Show that $F(x)$ is uniformly continuous on $(0, +\infty)$ if $f(t)=0, 0 \leq t < \frac{\pi}{2}$ and $\frac{{cos}^2t}{t},t\geq \frac{\pi}{2}$.

score 91 · Answer 11 · 2022-07-05 02:11:11

91

Views

Linearity of Uniformly Continuous functions

Published on 05 Jul 2022 - 2:11

score 214 · Answer 12 · 2022-07-12 10:12:58

214

Views

Prove that $1/x^2$ is not uniformly continuous on $(0,\infty)$ using $\varepsilon$-$\delta$ arguments

Published on 12 Jul 2022 - 10:12

score 306 · Answer 13 · 2022-07-13 07:53:43

306

Views

Evans' definition of $C(\bar{U})$ and the trace theorem in his PDE book

Published on 13 Jul 2022 - 7:53

score 76 · Answer 14 · 2022-07-13 13:48:06

76

Views

$\lvert y-z\rvert<\delta \implies \lvert y-\alpha\rvert<\delta_0$ and $\lvert z-\alpha\rvert<\delta_0$ continuity problem

Published on 13 Jul 2022 - 13:48

score 122 · Answer 15 · 2022-07-14 06:18:54

122

Views

If a function restriction to a dense subset of its domain is uniformly continuous, then there's an uniformly continuous extension of it

Published on 14 Jul 2022 - 6:18

List Question

composition of a continuous function with another function which is not uniformly continuous

Why are continuous functions, especially uniformly continuous function so important in generalization (estimating future values)?

uniformly continuity and boundedness of periodic function

Understanding uniform continuity - why is an upper estimate here allowed?

(Uniform) continuity in the proof of Müntz theorem

If $f$ is uniformly continuous on every finite subinterval of $[a,\infty)$, then is it necessary that $f$ is uniformly continuous on $[a,\infty)$?

If $f:[a,\infty) \to \mathbb R$ is uniformly continuous and $\lim_{x \to \infty}f(x)$ is finite, then show that $f$ is bounded on $[a,\infty)$

Can I find a modulus of continuity in this case?

The intuitive meaning of uniform continuity

Show that $F(x)$ is uniformly continuous on $(0, +\infty)$ if $f(t)=0, 0 \leq t < \frac{\pi}{2}$ and $\frac{{cos}^2t}{t},t\geq \frac{\pi}{2}$.

Linearity of Uniformly Continuous functions

Prove that $1/x^2$ is not uniformly continuous on $(0,\infty)$ using $\varepsilon$-$\delta$ arguments

Evans' definition of $C(\bar{U})$ and the trace theorem in his PDE book

$\lvert y-z\rvert<\delta \implies \lvert y-\alpha\rvert<\delta_0$ and $\lvert z-\alpha\rvert<\delta_0$ continuity problem

If a function restriction to a dense subset of its domain is uniformly continuous, then there's an uniformly continuous extension of it

Trending Questions

Popular # Hahtags

Popular Questions