Question

a problem about continuous functions on closed intervals

score 138 · Answer 1 · 2018-10-25 22:15:44

138

Views

a problem about continuous functions on closed intervals

Published on 25 Oct 2018 - 22:15

score 88 · Answer 2 · 2018-10-26 18:01:13

88

Views

How can a continuous function $f:[0,1] \cap{\mathbb{Q}}\rightarrow \mathbb{R}$ not be uniformly continuous?

Published on 26 Oct 2018 - 18:01

score 1.9k · Answer 3 · 2026-03-25 14:46:57

1.9k

Views

Let $f:(a,b) \to \mathbb{R}$ to be differentiable and unbounded. Prove: $f'$ is not bounded on $(a,b)$

Published on 25 Mar 2026 - 14:46

score 1k · Answer 4 · 2018-10-30 04:15:14

1k

Views

Proof Question: Continuous Functions on Compact Domains are uniformly continuous

Published on 30 Oct 2018 - 4:15

score 71 · Answer 5 · 2018-10-30 13:28:03

71

Views

Why does this argument that sin(1/x) is not uniform continuous on (0,1) fail for [0,1]?

Published on 30 Oct 2018 - 13:28

score 66 · Answer 6 · 2018-10-30 16:17:24

66

Views

Partial derivative under integral sign

Published on 30 Oct 2018 - 16:17

score 235 · Answer 7 · 2018-11-01 12:33:54

235

Views

Bounded Derivative Test

Published on 01 Nov 2018 - 12:33

score 1.1k · Answer 8 · 2026-03-25 14:39:54

1.1k

Views

Reverse Lipschitz condition

Published on 25 Mar 2026 - 14:39

score 289 · Answer 9 · 2018-11-06 18:37:13

289

Views

Proving Uniform Continuity of Fourier transform (Related to measure theory)

Published on 06 Nov 2018 - 18:37

score 176 · Answer 10 · 2018-11-07 16:45:17

176

Views

What kind of "geometric" regularity $f'^2$ gives on $f$

Published on 07 Nov 2018 - 16:45

score 88 · Answer 11 · 2018-11-08 02:58:35

88

Views

If $f:\Bbb{R}\to\Bbb{R}$ is uniformly continuous, then $f$ is bounded

Published on 08 Nov 2018 - 2:58

score 679 · Answer 12 · 2018-11-08 06:16:07

679

Views

Uniform continuity on a union of sets

Published on 08 Nov 2018 - 6:16

score 663 · Answer 13 · 2018-11-08 19:36:12

663

Views

Show that the support function of a bounded set is continuous.

Published on 08 Nov 2018 - 19:36

score 466 · Answer 14 · 2018-11-09 04:12:35

466

Views

$\epsilon-\delta$ proof that $f(x) = x \sin(1/x)$ on $(0,1)$ is uniformly continuous

Published on 09 Nov 2018 - 4:12

score 50 · Answer 15 · 2018-11-09 13:45:35

50

Views

Why does a uniformly continuous function on [a,b] in the reals need be closed AND bounded?

Published on 09 Nov 2018 - 13:45

List Question

a problem about continuous functions on closed intervals

How can a continuous function $f:[0,1] \cap{\mathbb{Q}}\rightarrow \mathbb{R}$ not be uniformly continuous?

Let $f:(a,b) \to \mathbb{R}$ to be differentiable and unbounded. Prove: $f'$ is not bounded on $(a,b)$

Proof Question: Continuous Functions on Compact Domains are uniformly continuous

Why does this argument that sin(1/x) is not uniform continuous on (0,1) fail for [0,1]?

Partial derivative under integral sign

Bounded Derivative Test

Reverse Lipschitz condition

Proving Uniform Continuity of Fourier transform (Related to measure theory)

What kind of "geometric" regularity $f'^2$ gives on $f$

If $f:\Bbb{R}\to\Bbb{R}$ is uniformly continuous, then $f$ is bounded

Uniform continuity on a union of sets

Show that the support function of a bounded set is continuous.

$\epsilon-\delta$ proof that $f(x) = x \sin(1/x)$ on $(0,1)$ is uniformly continuous

Why does a uniformly continuous function on [a,b] in the reals need be closed AND bounded?

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