Question

Let $(X_n)$ be a sequence of $\text{Unif}([-n,n])$ random variables. Why does $(X_n)$ not converge to $0$ in distribution?

score 392 · Answer 1 · 2022-12-22 17:05:00

392

Views

Let $(X_n)$ be a sequence of $\text{Unif}([-n,n])$ random variables. Why does $(X_n)$ not converge to $0$ in distribution?

Published on 22 Dec 2022 - 17:05

score 70 · Answer 2 · 2022-12-29 14:54:57

70

Views

An exercise I made for myself on Uniform Continuity and couldn't solve

Published on 29 Dec 2022 - 14:54

score 325 · Answer 3 · 2023-01-06 02:30:16

325

Views

Proving $f(x) = x^2$ is not uniformly continuous on the real ine

Published on 06 Jan 2023 - 2:30

score 65 · Answer 4 · 2023-01-06 08:26:15

65

Views

Is the function $f(x) = \frac{1}{x}$ uniformly continuous on the interval $(0.2 ,1)$?

Published on 06 Jan 2023 - 8:26

score 78 · Answer 5 · 2023-01-09 16:17:38

78

Views

What is the sence of "$f(x,y)$ is continuous at $x_0$ uniformly in $y$"?

Published on 09 Jan 2023 - 16:17

score 30 · Answer 6 · 2023-01-10 08:43:59

Let $f: [0,\infty) →\mathbb{R}$ uniformly continuous such that $\lim_{n \to +\infty} f(x+n)=0\; \forall x\geq 0$: show that $f(x) =0$ as $x\to\infty$

score 25 · Answer 7 · 2023-01-11 14:49:33

25

Views

proving that a function that's continous on $[a, +\infty$) with an horizontal or oblique asymptote (at +$\infty$) is uniformally continious

Published on 11 Jan 2023 - 14:49

score 78 · Answer 8 · 2023-01-11 20:58:49

78

Views

STFT uniform continuity

Published on 11 Jan 2023 - 20:58

score 43 · Answer 9 · 2023-01-12 13:32:38

43

Views

Show uniform continuity of $x\longmapsto\sqrt[4]{\lvert x\rvert}$

Published on 12 Jan 2023 - 13:32

score 64 · Answer 10 · 2023-01-14 20:18:54

64

Views

Integration over a Translated Set is Uniformly Continuous?

Published on 14 Jan 2023 - 20:18

score 106 · Answer 11 · 2023-01-16 21:52:44

106

Views

if $f(x)x^2$ is uniformly continuous than limit of $f(x)$ is equal to $0$

Published on 16 Jan 2023 - 21:52

score 134 · Answer 12 · 2023-01-23 17:43:47

134

Views

Prove function $f:\mathbb{R} \rightarrow \mathbb{R}$, $f(x)=e^{x^2}$ is not uniformly continuous.

Published on 23 Jan 2023 - 17:43

score 45 · Answer 13 · 2026-03-29 20:38:48

45

Views

If $f:[0, t] \to \mathbb R$ is continuous and has bounded variation, then its quadratic variation is $0$

Published on 29 Mar 2026 - 20:38

List Question

Let $(X_n)$ be a sequence of $\text{Unif}([-n,n])$ random variables. Why does $(X_n)$ not converge to $0$ in distribution?

An exercise I made for myself on Uniform Continuity and couldn't solve

Proving $f(x) = x^2$ is not uniformly continuous on the real ine

Is the function $f(x) = \frac{1}{x}$ uniformly continuous on the interval $(0.2 ,1)$?

What is the sence of "$f(x,y)$ is continuous at $x_0$ uniformly in $y$"?

Let $f: [0,\infty) →\mathbb{R}$ uniformly continuous such that $\lim_{n \to +\infty} f(x+n)=0\; \forall x\geq 0$: show that $f(x) =0$ as $x\to\infty$

proving that a function that's continous on $[a, +\infty$) with an horizontal or oblique asymptote (at +$\infty$) is uniformally continious

STFT uniform continuity

Show uniform continuity of $x\longmapsto\sqrt[4]{\lvert x\rvert}$

Integration over a Translated Set is Uniformly Continuous?

if $f(x)x^2$ is uniformly continuous than limit of $f(x)$ is equal to $0$

Prove function $f:\mathbb{R} \rightarrow \mathbb{R}$, $f(x)=e^{x^2}$ is not uniformly continuous.

If $f:[0, t] \to \mathbb R$ is continuous and has bounded variation, then its quadratic variation is $0$

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