Question

Weak topology net: $x_\alpha \rightarrow x $ iff $f(x_\alpha) \rightarrow f(x)$. Are open sets translation invariant?

score 103 · Answer 1 · 2017-09-03 17:00:24

103

Views

Weak topology net: $x_\alpha \rightarrow x $ iff $f(x_\alpha) \rightarrow f(x)$. Are open sets translation invariant?

Published on 03 Sep 2017 - 17:00

score 277 · Answer 2 · 2017-09-05 04:30:10

277

Views

Weak closedness in $L^p$ spaces

Published on 05 Sep 2017 - 4:30

score 476 · Answer 3 · 2026-03-25 16:59:08

476

Views

Goldstein's theorem

Published on 25 Mar 2026 - 16:59

score 327 · Answer 4 · 2017-10-03 10:30:11

327

Views

Is a precompact countable union of relatively compact sets necessarily relatively compact?

Published on 03 Oct 2017 - 10:30

score 148 · Answer 5 · 2017-10-15 19:25:20

148

Views

Trying to understand Weak Topology and Weak* Topology

Published on 15 Oct 2017 - 19:25

score 239 · Answer 6 · 2017-10-20 01:08:51

239

Views

Is the following application of the Banach-Alaoglu theorem sound?

Published on 20 Oct 2017 - 1:08

score 39 · Answer 7 · 2017-10-20 02:59:16

39

Views

Endomorphisms in the weak-* topology

Published on 20 Oct 2017 - 2:59

score 713 · Answer 8 · 2017-11-01 16:25:40

713

Views

Weak operator topology - the operator multiplication is not a continuous function

Published on 01 Nov 2017 - 16:25

score 757 · Answer 9 · 2017-11-03 02:07:53

757

Views

A linear form $f$ is continuous respect to weak$^{\star}$ topology if and only if there exists $x \in E$ such that $f(x')=x'(x)$ for all $x'\in E'$.

Published on 03 Nov 2017 - 2:07

score 480 · Answer 10 · 2017-11-04 19:55:10

480

Views

Let $E$ be a separable or reflexive infinite dimensional normed space, then there exists a sequence in $E'$ weak$^{*}$ convergent to $0$.

Published on 04 Nov 2017 - 19:55

score 844 · Answer 11 · 2017-11-08 22:28:24

844

Views

Counter example to first countable, second countable, and separable spaces

Published on 08 Nov 2017 - 22:28

score 996 · Answer 12 · 2026-03-26 12:42:16

996

Views

Brezis Exercise 3.9

Published on 26 Mar 2026 - 12:42

score 33 · Answer 13 · 2017-11-27 06:05:10

33

Views

$u_n$ is bounded in $L^1(\omega)$ implies $u_{n_{k}}$ weakly convergente in $L^2(\omega)$

Published on 27 Nov 2017 - 6:05

score 43 · Answer 14 · 2017-11-28 16:12:19

43

Views

$T: E\to F$ weak continuous, $E, F$ locally convex

Published on 28 Nov 2017 - 16:12

score 90 · Answer 15 · 2017-11-28 18:12:28

90

Views

weak-$\ast$-continuous, topological isomorphism, functional analysis

Published on 28 Nov 2017 - 18:12

List Question

Weak topology net: $x_\alpha \rightarrow x $ iff $f(x_\alpha) \rightarrow f(x)$. Are open sets translation invariant?

Weak closedness in $L^p$ spaces

Goldstein's theorem

Is a precompact countable union of relatively compact sets necessarily relatively compact?

Trying to understand Weak Topology and Weak* Topology

Is the following application of the Banach-Alaoglu theorem sound?

Endomorphisms in the weak-* topology

Weak operator topology - the operator multiplication is not a continuous function

A linear form $f$ is continuous respect to weak$^{\star}$ topology if and only if there exists $x \in E$ such that $f(x')=x'(x)$ for all $x'\in E'$.

Let $E$ be a separable or reflexive infinite dimensional normed space, then there exists a sequence in $E'$ weak$^{*}$ convergent to $0$.

Counter example to first countable, second countable, and separable spaces

Brezis Exercise 3.9

$u_n$ is bounded in $L^1(\omega)$ implies $u_{n_{k}}$ weakly convergente in $L^2(\omega)$

$T: E\to F$ weak continuous, $E, F$ locally convex

weak-$\ast$-continuous, topological isomorphism, functional analysis

Trending Questions

Popular # Hahtags

Popular Questions