Question

weak topology has less open set than strong topology (in Banach spaces). Why?

score 982 · Answer 1 · 2018-07-31 14:18:23

982

Views

weak topology has less open set than strong topology (in Banach spaces). Why?

Published on 31 Jul 2018 - 14:18

score 387 · Answer 2 · 2018-07-31 15:48:45

387

Views

Linear functional $\psi:X \to \mathbb{R}$ is $W$-weakly continuous if and only if it belongs to $W$

Published on 31 Jul 2018 - 15:48

score 82 · Answer 3 · 2018-07-31 21:02:45

82

Views

Examples of elements in $(X^)^$ that are not evaluation maps

Published on 31 Jul 2018 - 21:02

score 65 · Answer 4 · 2018-08-16 06:32:07

65

Views

Is $E^{\prime\prime}$ weak*-separable for separable Banach spaces?

Published on 16 Aug 2018 - 6:32

score 166 · Answer 5 · 2018-08-24 20:11:08

166

Views

When does the continuous dual of the weak operator topology consist only of finite linear combinations of evaluations?

Published on 24 Aug 2018 - 20:11

score 78 · Answer 6 · 2018-08-29 11:55:44

78

Views

When $E$ has finite dimension, then the weak topology and the strong topologie are the same.

Published on 29 Aug 2018 - 11:55

score 339 · Answer 7 · 2018-08-29 20:05:01

339

Views

In "Analyse fonctionnelle" of Brezis, in chapter III why do we need Banach spaces ? (especially for Kakutani's theorem)

Published on 29 Aug 2018 - 20:05

score 1.2k · Answer 8 · 2018-08-30 21:13:30

1.2k

Views

Compactness / sequentially compact / reflexive space / separable spaces / weak topology

Published on 30 Aug 2018 - 21:13

score 222 · Answer 9 · 2018-08-31 13:29:12

222

Views

Space of measures has the Dunford-Pettis property?

Published on 31 Aug 2018 - 13:29

score 140 · Answer 10 · 2018-09-07 10:19:15

140

Views

If for every $e\in E\setminus\{0\},$ there exists $e^\in A$ such that $e^(e)\neq 0,$ then $A$ is weak-star dense in $E^*?$

Published on 07 Sep 2018 - 10:19

score 394 · Answer 11 · 2018-10-04 05:58:13

394

Views

Can we prove that in a convex space, Weakly closed=> weak* closed ??

Published on 04 Oct 2018 - 5:58

score 311 · Answer 12 · 2018-10-05 15:33:24

311

Views

Closed convex hull of pure states of non-unital $C^*$-algebras

Published on 05 Oct 2018 - 15:33

score 356 · Answer 13 · 2018-10-23 09:00:55

356

Views

Question about a weak*-norm continuity of a linear operator

Published on 23 Oct 2018 - 9:00

score 200 · Answer 14 · 2018-11-13 06:14:24

200

Views

For an infinite dimensional Banach space, $X^$ when given the weak topology is of the first category in itself

Published on 13 Nov 2018 - 6:14

score 126 · Answer 15 · 2018-11-13 20:29:37

126

Views

Neighborhood of zero on weak topology

Published on 13 Nov 2018 - 20:29

List Question

weak topology has less open set than strong topology (in Banach spaces). Why?

Linear functional $\psi:X \to \mathbb{R}$ is $W$-weakly continuous if and only if it belongs to $W$

Examples of elements in $(X^)^$ that are not evaluation maps

Is $E^{\prime\prime}$ weak*-separable for separable Banach spaces?

When does the continuous dual of the weak operator topology consist only of finite linear combinations of evaluations?

When $E$ has finite dimension, then the weak topology and the strong topologie are the same.

In "Analyse fonctionnelle" of Brezis, in chapter III why do we need Banach spaces ? (especially for Kakutani's theorem)

Compactness / sequentially compact / reflexive space / separable spaces / weak topology

Space of measures has the Dunford-Pettis property?

If for every $e\in E\setminus\{0\},$ there exists $e^\in A$ such that $e^(e)\neq 0,$ then $A$ is weak-star dense in $E^*?$

Can we prove that in a convex space, Weakly closed=> weak* closed ??

Closed convex hull of pure states of non-unital $C^*$-algebras

Question about a weak*-norm continuity of a linear operator

For an infinite dimensional Banach space, $X^$ when given the weak topology is of the first category in itself

Neighborhood of zero on weak topology

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