Heat equation solution of type $v(\frac{x^{2}}{t})$

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I have stucked in heat Equation $u_{t}=u_{xx}$

I look for a solution of type $v(\frac{x^{2}}{t})$.

I set $z=\frac{x^{2}}{t}$ and i end up in the ode: $\frac{16}{t}v''(z)+(\frac{8}{x^{2}}+\frac{4t}{x^{3}}-1)v'(z)=0$

Because,

$v_{t}(x,t)=v'(z)\frac{x^{4}}{t^{4}}$

$u_{xx}(x,t)=v''(z)\frac{16x^{4}}{t^{4}}+v'(z)\frac{8x^{2}}{t^{2}}+v'(z)\frac{4x}{t^{2}}$

According to Lawrence C Evans in Partial Differential Equation in page 87,we should end up in the ode: $4zv''(z)+(2+z)v'(z)=0$

Who i am wrong?