Let the tree described by $T(n) = 4T(n/4)+2T(5n/8)+T(n/8)+\theta(1)$
Can someone explains why the height is $\log_{8/5}{n}$ I don't know how to proceed
2026-03-27 15:10:35.1774624235
Height of the tree : $T(n) = 4T(n/4)+2T(5n/8)+T(n/8)+\theta(1)$
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The height of the tree is determined by the slowest process, $T(n/b)$. The last leaf on the tree has $T(n/b^{\text{height}})=O(1)$, and therefore the height of the tree is: $$\text{height}=\log_b n = \log_{8/5}n$$