Help me solve this

Question

$(1-(1-(1-n)^{-1})^{-1})^{-1}$

Please tell me how to solve the abv sum. The ans is $n$

Answer 1

$(1-(1- (1-n)^{-1})^{-1})^{-1} =\left(1- \left(1 + \dfrac{1}{n-1}\right)^{-1}\right)^{-1}=\left(1-\left(\dfrac{n}{n-1}\right)^{-1}\right)^{-1}=\left(1-\dfrac{n-1}{n}\right)^{-1}= \left(\dfrac{1}{n}\right)^{-1}= n$