$$\int \frac{\sqrt{t+2}}{e^t}\,dt$$
I have tried integration by parts, but that is leading me no where. I typed it into Wolfram Alpha, but don't know much about erf function, just know what wikipedia page stated.
Could I please have some help solving this.
$$ \int \sqrt{x+2}\ e^{-x} \ dx$$
Let $t^{2} = x +2 $.
$$ = \int t e^{-(t^{2}-2)} \ 2 t \ dt = 2 e^{2} \int t \left( t \ e^{-t^{2}} \right) \ dt $$
Now integrate by parts by letting $u = t$ and $dv = t e^{-t^{2}} \ dt$.
$$ = 2 e^{2} \left( - \frac{1}{2} t e^{-t^{2}} + \frac{1}{2} \int e^{-t^{2}} \ dt \right) $$
$$ = 2e^{2} \left( - \frac{1}{2} t e^{-t^{2}} + \frac{1}{2} \frac{\sqrt{\pi}}{2} \text{erf}(t) + C \right) $$
$$ = 2e^{2} \left(- \frac{1}{2} \sqrt{x+2} \ e^{-(x+2)} + \frac{1}{2} \frac{\sqrt{\pi}}{2} \text{erf}(\sqrt{x+2}) \right) + C$$
$$ = -\sqrt{x+2} \ e^{-x} + \frac{\sqrt{\pi}}{2} e^{2} \text{erf}(\sqrt{x+2}) + C$$