I'm trying to prove the following equation by induction, but my base case isn't working.
for all n>2.
For my base case I did n=3, and on the LHS I got 8/9 and the RHS I got 2/3.
Helppp.
The left hand side is
$$\left(1-\frac{1}{2^2}\right)\left(1-\frac{1}{3^2}\right)=\frac{3}{4}\frac{8}{9} = \frac23$$
and so is the right hand side:
$$\frac{3 + 1}{2\cdot 3} = \frac46=\frac23$$
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The left hand side is
$$\left(1-\frac{1}{2^2}\right)\left(1-\frac{1}{3^2}\right)=\frac{3}{4}\frac{8}{9} = \frac23$$
and so is the right hand side:
$$\frac{3 + 1}{2\cdot 3} = \frac46=\frac23$$