Help with the integral $\int \frac { x } { x + \tan x } \mathrm d x$

Question

Help with the integral:

$\int \frac { x } { x + \tan x }\mathrm d x$

My try follows: using identity $\tan(x)= \frac { \sin x} { \cos x }$ yields

$$\int \frac { x\cos x } { x\cos x + \sin x }\mathrm d x$$ Now what?