Hermitian Matrix multiplied by complex numbers

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I have a question regarding self-adjoint(hermitian) matrices, and their properties when multiplied by an imaginary number. The matrix in question is: $$\mathbf{A} = c \begin{bmatrix} 0&0&0&0\\ 0&0&2i&0\\ 0&-2i&0&0\\ 0&0&0&0 \end{bmatrix}\\ \textit{where} \; \mathbf{A}^\dagger=\mathbf{A} $$ This should be pretty simple to answer to, but I am having a brain fart at the moment: if we assume $c=\frac{i}{2}$, then: $$\mathbf{A} = \begin{bmatrix} 0&0&0&0\\ 0&0&-1&0\\ 0&1&0&0\\ 0&0&0&0 \end{bmatrix}\\ \textit{where} \; \mathbf{A}^\dagger\neq\mathbf{A} $$ Do hermitian operators stop to be so if multiplied by a complex number?

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When $A$ is Hermitian, we have $(cA)^\dagger-cA=c^\dagger A^\dagger-cA=(c^\dagger-c)A$. Therefore $cA$ is Hermitian if and only if $A=0$ or $c$ is real.