I have
$$y'''- 3\,y'- x\,y = 0.$$
How to convert this to three first order differential equations?
I got stuck for using Let $z=y''$
I have
$$y'''- 3\,y'- x\,y = 0.$$
How to convert this to three first order differential equations?
I got stuck for using Let $z=y''$
Let $y_1=y$, $y_2=y'$ and $y_3=y''$. Then $$\begin{align} y_1'&=y_2\\ y_2'&=y_3\\ y_3'&=y'''=\text{ fill the blank}. \end{align}$$